Answer:
import java.util.Scanner;
public class FindMatchValue {
public static void main (String [] args) {
final int NUM_VALS = 4;
int[] userValues = new int[NUM_VALS];
int i = 0;
int matchValue = 0;
int numMatches = -99; // Assign numMatches with 0 before your for loop
userValues[0] = 2;
userValues[1] = 2;
userValues[2] = 1;
userValues[3] = 2;
matchValue = 2;
numMatches=0;
for(i=0;i<NUM_VALS;i++)
{
if(userValues[i]==matchValue)//cheking if the array element is equal to match value.
{
numMatches++;
}
}
System.out.println(numMatches);//printing the matchvalue.
}
}
Output:-
3
Explanation:
First I have set the value numMatches to 0 before the loop.Then I have user the for loop to iterate over the array.In the for loop I am checking that the array element is equal to the matchValue or not if it is equal then increasing the numMatches by 1.Then at last print the value of numMatches.
Answer:
I believe it is windows 8
Python can be used to implement central of tendencies such as mean, median and mode using the statistic module
The program in Python, where comments are used to explain each line is as follows:
#This imports the statistics module
import statistics
#This defines the function that calculates the mode
def calcMode(myList):
#This prints the mode
print(statistics.multimode(myList))
#This defines the function that calculates the median
def calcMedian(myList):
#This prints the median
print(statistics.median(myList))
#The main method begins here
#This initializes the list
myList = []
#The following iteration gets input for the list
for i in range(10):
myList.append(int(input()))
#This calls the calcMode method
calcMode(myList)
#This calls the calcMedian method
calcMedian(myList)
Read more about similar programs at:
brainly.com/question/25026386
Answer:
underscore hope that helps
Explanation:
Answer:
All flags are On ( c, z , N )
Explanation:
Given data:
4-bit operation
Assuming 2's complement representation
<u>Determine status flags that are on after performing </u> 1010+0110
1 1
1 0 1 0
0 1 1 0
1 0 0 0 0
we will carry bit = 1 over
hence C = 1
given that: carry in = carry out there will be zero ( 0 ) overflow
hence V = 0
also Z = 1
But the most significant bit is N = 1
