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Leokris [45]
2 years ago
13

How to find unknown side

Mathematics
1 answer:
Elan Coil [88]2 years ago
3 0

Answer:

C = 10

Step-by-step explanation:

Find the last side of the triangle using the Pythagorean theorem.

a^{2} +b^{2} =c^{2}

You have a and b already, a = 6, b = 8

6^{2} +8^{2} =c^{2} \\\\

solve this to get

64 + 36 = \sqrt{100}

C = 10

Apply the same to the other 2 triangles. C is your longest side!

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The scooter was rented for 3 hours
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Find the collame of boid of dimension 16cm X 10m x 6cm.​
swat32

Question: Find the volume of cuboid of dimension 16cm X 10cm x 6cm.

Answer: Given Length=16cm, Breadth=10cm, Height=6cm

Using Volume formula for cuboid:-

volume = l \times b \times h

→16 \times 10 \times 6

→960 \: cm^{3}

So, volume of cuboid is <u>9</u><u>6</u><u>0</u><u> </u><u>cm³</u>

7 0
2 years ago
What is the volume, in cubic in, of a rectangular prism with a height of 8in, a width of 5in, and a length of 9in?
Maslowich

Answer:

360 in ^3

Step-by-step explanation:

The volume is given by

V = l*w*h

 = 8 * 5 * 9

  = 360 in ^3

3 0
3 years ago
Mr. Bartley is taking the theater club on a field trip to see the musical wicked. The school treasurer asked Mr. Bartley for the
Darya [45]

Answer: Tickets cost $25 and each person must contribute $2 for the bus. There are 52 people going on the trip.


Step-by-step explanation:

Given: Mr. Bartley is taking the theater club on a field trip [which must include bus or other vehicle] to see the musical wicked. The school treasurer asked Mr. Bartley for the group's total ticket cost.

He wrote the following cost function for the school treasurer.

Total Cost =52(25+2)

Since cost function is a function based on number of people and per head cost.

So, the statement which best describe the cost function is "Tickets cost $25 and each person must contribute $2 for the bus. There are 52 people going on the trip."


5 0
3 years ago
Read 2 more answers
A fair coin is to be tossed 20 times. Find the probability that 10 of the tosses will fall heads and 10 will fall tails, (a) usi
lbvjy [14]

Using the distributions, it is found that there is a:

a) 0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

b) 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

c) 0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item a:

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 20 tosses, hence n = 20.
  • Fair coin, hence p = 0.5.

The probability is <u>P(X = 10)</u>, thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{20,10}.(0.5)^{10}.(0.5)^{10} = 0.1762

0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item b:

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • The binomial distribution is the probability of <u>x successes on n trials, with p probability</u> of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

The probability of an exact value is 0, hence 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item c:

For the approximation, the mean and the standard deviation are:

\mu = np = 20(0.5) = 10

\sigma = \sqrt{np(1 - p)} = \sqrt{20(0.5)(0.5)} = \sqrt{5}

Using continuity correction, this probability is P(10 - 0.5 \leq X \leq 10 + 0.5) = P(9.5 \leq X \leq 10.5), which is the <u>p-value of Z when X = 10.5 subtracted by the p-value of Z when X = 9.5.</u>

X = 10.5:

Z = \frac{X - \mu}{\sigma}

Z = \frac{10.5 - 10}{\sqrt{5}}

Z = 0.22

Z = 0.22 has a p-value of 0.5871.

X = 9.5:

Z = \frac{X - \mu}{\sigma}

Z = \frac{9.5 - 10}{\sqrt{5}}

Z = -0.22

Z = -0.22 has a p-value of 0.4129.

0.5871 - 0.4129 = 0.1742.

0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

A similar problem is given at brainly.com/question/24261244

6 0
3 years ago
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