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anyanavicka [17]
3 years ago
14

Латна монтаж на работа

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0

Answer:

$183.75

Step-by-step explanation:

divide by 12 (hours)

147/12=12.25

multiply by 15 (hours)

12.25*15=183.75

Hope this helps! :)

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Help please! Using the graph below determine which statement is true
JulsSmile [24]

Answer:

The answer is 'C' "The slope of line BC is equal to the slope of line segment DE"

Step-by-step explanation:

This is correct. I checked my answer for this about 3 times. If this isn't correct then my next bet is answer 'D'

{-Please give me credit for trying, Thank you-}

4 0
3 years ago
Factor ab + bc + b2 + ac.
Alona [7]
<span>ab + bc + b</span>²<span> + ac = 
(b</span>² + bc<span>)+(ab + ac) = 
b(b+ c)+a(b + с) = 
(b + c)(b + a)</span>
5 0
3 years ago
Read 2 more answers
A car traveled 23 miles in 15 min how many miles per hour was it traveling
creativ13 [48]

Answer:

    _____

1.533333  miles per hour

Hope this helped

4 0
3 years ago
Solve for x in the equation x2 - 4x-9 = 29.
erastova [34]

Answer:

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

Step-by-step explanation:

One is given the following equation;

x^2-4x-9=29

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;

x^2-4x-9=29

x^2-4x-38=0

This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

ax^2+bx+c

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Substitute the coefficients of the given equation in and solve for the roots;

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}

Simplify,

\frac{-(-4)(+-)\sqrt{(-4)^2-4(1)(-38)}}{2(1)}\\\\=\frac{4(+-)\sqrt{16+152}}{2}\\\\=\frac{4(+-)\sqrt{168}}{2}\\\\=\frac{4(+-)2\sqrt{21}}{2}\\\\=2(+-)\sqrt{21}

Therefore, the following statement can be made;

x=2+\sqrt{21}\\\\x=2-\sqrt{21}

8 0
3 years ago
Find four consecutive integers such that the sum of the second and fourth is 132
Ulleksa [173]

Remark

As long as the representation shows the numbers come one after another, you can get x to be anything.

Givens

x Can be the second number

x - 1 Can be the first number

x + 1 Can be the third number

x + 2 Can be the fourth number

Equation

x + x + 2= 132

Solution

2x + 2 = 132

2x = 130

x = 65

So the 4 numbers are 64 65 66 67

Check

The second and fourth numbers added together = 65 + 67 = 132

7 0
3 years ago
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