Answer:
y₁=x₁+0.04x₂
y₂=x₂+0.06x₁
Step-by-step explanation:
In the first year, number of people who live:
In the city= x₁
In the suburb=x₂
New Population in the next year
In the city= y₁
In the suburb=y₂
If each year 6% of the city population moves to the suburb,
New Suburb Population=Previous Population+Immigrants
y₂=x₂+0.06x₁
If each year 4% of the suburb population moves to the city,
New City Population=Previous Population+Immigrants
y₁=x₁+0.04x₂
y₁=x₁+0.04x₂
y₂=x₂+0.06x₁
Answer:
The value of Mary's investment after two years = £12362.7
Step-by-step explanation:
P = Principal / initial amount
R = rate of interest per cent per year
T = number of years
A = final amount at the end of T years
Then:
A = P*(1 + R/100)^2
In our example:
P = £12000
R = 1.5 per cent per year
T = 2 years
Thus:
A = 12000*(1 + 1.5/100)^2
= 12000*(1 + 0.015)^2
= 12000*(1.015)^2
= 12000*(1.030225)
= 12362.7
Value of investment after two years = £12362.7
The first one is cost of jam $4, cost of soup $7
Tyler (T)= 17.04 gallons
Maria=6.2(T), Maria= 6.2x17.04=105.65 gallons
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