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Leona [35]
3 years ago
5

NEED HELP ASAP! 50 POINT QUESTION.

Mathematics
2 answers:
siniylev [52]3 years ago
5 0
It is B and D because it is the only one that matches the input and outputs. D shows a perfect graph of the points while B shows the points themselves. They cannot be a linear function since they are not linear so it is not E or F.
irina [24]3 years ago
4 0
The correct answer would be B and D I hope this helped you and I hope you have a good day and tomorrow and on and on... you are an amazing person and yah
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Divide. Write in simplest form.<br><br> 2/3 divided by 1/5
Nezavi [6.7K]

Answer:

3 1/3 or 3.3(repeated)

Step-by-step explanation:

2/3 ÷ 1/5

= 2/3 × 5

= 10/3

= 3 1/3 or 3.3(repeated)

I hope this helped!

3 0
3 years ago
PLEASE HELP ASAP I'M TIMED
jekas [21]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
What is the volume of the right rectangular prism
11111nata11111 [884]
I don’t get this sorry
8 0
3 years ago
kyle models a sum of two integers. he uses more negative (red) counters than postive (yellow) counters. what do you predict abou
Firdavs [7]

the sign would probably be a negative. imagine this - - - - - - and then + + +, cancel out the negatives and plus then you are left with more negatives than positive so the sign will take the negative sign.

6 0
3 years ago
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