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fredd [130]
3 years ago
6

On the following graph, type the solution that has a multiplicity of (2) or a double root. If there is no double

Mathematics
1 answer:
Temka [501]3 years ago
8 0

Answer:

3

Step-by-step explanation:

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INSTRUCTIONS<br> Solve the division problems<br> Name
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13

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Do the divison! :D It's hard to write out on here, but you can find a lot of other online resources on how to do it, I reccomend Khan Academy.

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The spirit squad is making a sign for the boy’s basketball team. It has a roll of paper that is 4 1/2 feet wide, but cannot use
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H is less than of equal to 8

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3 years ago
Read 2 more answers
What is the product of 4n^+3=7n?
Inessa [10]
So if you solve for n
4n^2+3=7n
make into trinomial
subtract 7n from both sides
4n^2-7n+3=0
if we can factor this, then we can asume that the factors are equal to zero becase if
xy=0 then assume x and/or y=0 so

to factor an equation in ax^2+bx+c where a is greater than 1 then
b=t+z
a times c=t times z
to factor 4n^2-7n+3 you do
4 times 3=12
what 2 numbers multiply to get 12 and add to get -7
the numbers are -3 and -4 so
split up the -7
4n^2-4n-3n+3
group
(4n^2-4n)+(-3n+3)
undistribute
(4n)(n-1)+(-3)(n-1)
reverse distributive property
ab+ac=a(b+c)
(4n-3)(n-1)=0
set each to zero
4n-3=0
add 3 to both sides
4n=3
divide both sides by 4
n=3/4

n-1=0
add 1 to both sides
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4 0
3 years ago
A man has Rs 1900. he lent some of it at 5% p.a and rest at9% p.a. The total amount of interest which he got after4 years was Rs
Helen [10]

Answer:

The sum is Rs 1,250 and Rs 650

Step-by-step explanation:

Let the amounts be represented as $x and $y

The sum of both is 1900

Thus;

x + y = 1,900 •••••(i)

Mathematically, the interest on the amount borrowed is;

I = PRT/100

where p is the principal, representing the amount borrowed

R is the rate

T is the time

for the first amount of $x ; we have interest as;

I = (x * 5 * 4)/100 = 20x/100

for the second, we have

I = (y * 9 * 4)/100 = 36y/100

The sum of both is 580

Thus;

20x/100 + 36y/100 = 580

20x + 36y = 58000 •••••(ii)

From equation i;

x = 1,900 - y

Substitute this into equation ii

We have this as;

20(1900-y) + 36y = 58,000

38000 - 20y + 36y = 58,000

16y = 58000 - 38000

16y = 20,000

y = 20,000/16

y = 1250

From equation 1;

x + y = 1900

x = 1900-y

x = 1900-1250

y = 650

4 0
2 years ago
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