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nataly862011 [7]
3 years ago
11

salma is 1.45 meters tall. at 3p.m she measures the length of a tree's shadow to 29.35 meters. she stands 24.3 meters away from

the tree, so that the tip of her shadow meets the tip of the treels shadow. find the height of the tree to the nearest hundreth of a meter.
Mathematics
2 answers:
jeka943 years ago
8 0

Answer:

kimjnuhbygvtcfrdxe

Step-by-step explanation:

Sophie [7]3 years ago
7 0

Answer:

23.67

Step-by-step explanation:

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The ratio of males to females in a cycling club is 5:3.
taurus [48]

Answer:

3/2

Step-by-step explanation:

The ratio of males to females in a cycling club is 5:3.

1/3 of the males are under 18

2/9 of the females are under 18

The fraction of the club members that are under 18 is calculated as:

Male: Female = Male/Female

We are told in the above question:

1/3 of the males are under 18

2/9 of the females are under 18

Hence:

1/3 / 2/9

= 1/3 ÷ 2/9

= 1/3 × 9/2

= 3/2

The fraction of the club members that are under 18 is 3/2

6 0
3 years ago
What is the value of 3-(-2)
Vanyuwa [196]

Answer:

5

Step-by-step explanation:

3-(-2)=5

6 0
3 years ago
Read 2 more answers
Decide what number must be added to each binomial to make a perfect square trinomial
8090 [49]

To make a perfect square, we must know that 22/2 = 11. In this case:

(x + 11)^2 = x^2 + 22x + 121

4 0
3 years ago
Which is the simplified form of the expression
erica [24]

Answer:

4 / x¹⁴y⁸

Step-by-step explanation:

eliminate parenthese by multiplying all exponents inside parentheses by the exponent outside the parentheses:

1/2⁶ ÷ 1/4⁴ = 1/64 ÷ 1/256 which equals 256/64 or 4

x⁻⁶y⁴ ÷ x⁸y¹² = x⁻¹⁴y⁻⁸ = 1/x¹⁴ · 1/y⁸

put it all together to get:

4÷(x¹⁴y⁸)

3 0
3 years ago
The normal distribution An automobile battery manufacturer offers a 31/54 warranty on its batteries. The first number in the war
seraphim [82]

Answer:

1) if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2) a standard deviation of 6.0843 results in a 1.07% replacement rate

3) using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

Step-by-step explanation:

based on the given data;

x will represent the random variable such that the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months

so

x → N( U = 45, ∝ = 5.6)

Under the warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charges to the consumer.

if the battery fails after 31 months but within 54 months, the manufacturer provides a prostrated credit towards the purchase of anew battery

1) If the manufacturer's assumptions are correct,

p(x < 3) = p( [x-u / ∝ ] < [ 31-45 / 5.6] )

= p( z < -2.5 )

using the standard normal table,

value of z = 0.0062 ≈ 0.62%

so if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.

2)

The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect, so a standard deviation of ? results in a 1.07%

so lets say;

p ( x < 31 ) = ( 1.07%) = 0.0107

p ( [x-u / ∝ ] < [ 31-45 / ∝] ) = 0.0107

now from the standard table

-2.301 is 1.07%

so

( 31 - 45 / ∝ ) = -2.301

-14 / ∝ = -2.301

∝ = -14 / - 2.301

∝ = 6.0843

therefore a standard deviation of 6.0843 results in a 1.07% replacement rate

3)

Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?

p( 31 < x < 54 ) = p ( [31 - u / ∝ ] < [ x-u / ∝]  < [ 54 - 45 / ∝] )

= p ( [31 - 45 / 6.0843 ] < [ x-u / ∝]  < [ 54 - 45 / 6.0843] )

= p ( -2.301 < z < 1.4792 )

= p(Z < 1.5) - p(Z < -2.3)

= 0.9393 - 0.0108

= 0.919 ≈ 91.9%

therefore using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit

8 0
3 years ago
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