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Zinaida [17]
3 years ago
10

ILL BRAINLIEST YOU PLEASE HELP ME

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0
15.8 I believe. Since 20 isn’t a option 15 is the closest. Good luck I have good faith I have you the right answer
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Find X.<br> Round to the nearest tenth.<br><br> Law of Cosines : c2 = 22 + b2 - 2ab cos C
fiasKO [112]

Answer:

70.5°

Step-by-step explanation:

22² = (20)²+(18)² - 2(20)(18) cos X

484 = 400 + 324 - 720 cos X

-240 = -720 cosx

1/3 = cos X

cos^{-1}(\frac{1}{3}) = X

X = 70.52877937

7 0
3 years ago
−6x+14&lt;−28 OR 9x+15≤−12
Serhud [2]

Answer:x>7 or x ≤ -3

Solving the 1st inequality

-6x +14 < -28 --------------- (Collect like terms)

-6x < -28 - 14

-6x < - 42 -------------------- (Divide both sides by -6)

Note: If you decide an inequality expression by a negative value, the inequality sign changes)

-6x/-6 > -42/-6

x > 7

Solving the 2nd inequality

9x + 15 ≤ −12 ----------- (Collect like terms)

9x ≤ −12 - 15

9x ≤ −27 ------------------(Divide both sides by 9)

9

9x/9 ≤ −27/9

x ≤ -3

Bring both results together, we get

x>7 or x ≤ -3

The final result is complex (i.e. can't be combined together).

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The Question is: Write 1/3 and 3/4 as a pair of fractions with a common denominator
cupoosta [38]
1/3*4= 4/12
3/4*3= 9/12
Answer is 4/12 and 9/12.
5 0
3 years ago
What is the value of the expression 5ab-2c, where a =2, b=3 and c=0?
ira [324]

Answer:

30

Step-by-step explanation:

5*2*3 - 2*0 = 30 - 0 = 30

5 0
3 years ago
Look at the rectangle and the square:
OlgaM077 [116]

Answer:

Sam is incorrect

Step-by-step explanation:

We can calculate the lengths of the diagonals using Pythagoras' identity.

The diagonals divide the rectangle and square into 2 right triangles.

Consider Δ SRQ from the rectangle

SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )

SQ = \sqrt{180} ≈ 13.4 in ( to 1 dec. place )

Consider Δ ONM from the square

OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )

OM = \sqrt{72} ≈ 8.5 in ( to 1 dec. place )

Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4

Then diagonal OM is not twice the length of diagonal SQ

5 0
3 years ago
Read 2 more answers
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