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kherson [118]
3 years ago
15

Alyssa says that n = 6 is the solution of the equation 12n = 84. How can you check whether she is correct?

Mathematics
1 answer:
Vikki [24]3 years ago
4 0

Answer:

No. The answer is 72

Step-by-step explanation:

As 12x6=72

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The answer to this is B
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Solve for x: Log4(x+8)=3
viktelen [127]
If log_{4}(x+8)=3
Then 4^3=x+8
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3 0
4 years ago
What is the value of h in the equation 8h = 60
irga5000 [103]

Answer:

h= 7.5

Step-by-step explanation:

8h=60

One solution was found :

                  h = 15/2 = 7.500

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    8*h-(60)=0

Step by step solution :

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  8h - 60  =   4 • (2h - 15)

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    4   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    2h-15 = 0

Add  15  to both sides of the equation :

                     2h = 15

Divide both sides of the equation by 2:

                    h = 15/2 = 7.500

One solution was found :

                  h = 15/2 = 7.500

Processing ends successfully

7 0
3 years ago
Read 2 more answers
If you roll two fair dice repeatedly, what is the probability that you will get a sum of 4 before you get a sum of 5 ? (a) (b) (
AlexFokin [52]

Answer:

The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

Step-by-step explanation:

Given : If you roll two fair dice repeatedly.

To find : What is the probability that you will get a sum of 4 before you get a sum of 5 ?

Solution :

When two dice are rolled the outcomes are

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Total number of outcomes = 36

Favorable outcome get a sum of 4 before you get a sum of 5 is (1,3) ,(2,2) and (3,1) = 3

The probability that you will get a sum of 4 before you get a sum of 5 is

P=\frac{3}{36}

P=\frac{1}{12}

Therefore, The probability that you will get a sum of 4 before you get a sum of 5 is \frac{1}{12}

5 0
3 years ago
Which choice is equivalent to the expression below? √-49<br><br>btw its 7i
Nastasia [14]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
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