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3 years ago

PLSSSSSSS HELPPPPPPPPPPPP!!!!!!!!!!!!!!!

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

7 0

The answer is would be

c

Airida [17]3 years ago

5 0

I think the answer is c hope this helps

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A bag contains different colored jelly beans. In the bag, there are 5 red jelly

ikadub [295]

Answer:

1/4

Step-by-step explanation:

3/12 = 1/4

(We got 12 by adding all the numbers together.)

4 0

3 years ago

Two consecutive integers have sum of 137

Mazyrski [523]

You would do x+ (x+1)=137
2x+1=137
Subtract 1 from each side
2x=136
x=68.
Add 1 to 68, since they are consecutive integers.
The answer is 68 and 69

5 0

3 years ago

Read 2 more answers

A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so

Debora [2.8K]

Let $A(t)$ = amount of salt (in pounds) in the tank at time $t$ (in minutes). Then $A(0) = 11$ .

Salt flows in at a rate

$\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}$

and flows out at a rate

$\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}$

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

$\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}$

which I'll solve with the integrating factor method.

$\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95$

$-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}$

$\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}$

Integrate both sides. By the fundamental theorem of calculus,

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}$

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)$

$\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}$

$\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}$

$\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}$

After 1 hour = 60 minutes, the tank will contain

$A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131$

pounds of salt.

7 0

2 years ago

The correct simplification of (7x3y3)2.

anyanavicka [17]

<span>49 x^6 y^6
Assuming the 2 is an exponent.
I had the same question.
Just square </span>everything.
Ex. 7^2 = 49

Brainiest would be nice.

7 0

3 years ago

Read 2 more answers

Find the PERIMETER of this triangle

olga2289 [7]

First we need to find the missing side, use

$a = \sqrt{ {c}^{2} - {b}^{2} }$
So the missing leg = the sqrt of the hypotenuse squared minus the other leg squared.

Let's substitute the numbers,

$a = \sqrt{ {10}^{2} - {6}^{2} }$
Solve for the squares,

$a = \sqrt{100 - 36}$
Subtract,

$a = \sqrt{64}$
Solve for the root,

$a = 8$
~~

So our missing length is 8.

To find the perimeter of the triangle, simply add all the sides....

~~

$8 + 10 + 6 = 24$

~~

Answer : 24

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

4 0

3 years ago

Read 2 more answers