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strojnjashka [21]
3 years ago
14

PLSSSSSSS HELPPPPPPPPPPPP!!!!!!!!!!!!!!!

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
7 0
The answer is would be

c
Airida [17]3 years ago
5 0
I think the answer is c hope this helps
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Name the subset of the real number to which each number belongs<br> 1. square root of 11<br> 2. -7
Ganezh [65]
1 and 2 are natural numbers
-7  belongs to set of integers
sqrt 11  is a member of the set of irrational numbers
6 0
3 years ago
Help quick please with explain
Paul [167]

Answer:

20= v+9+( -16 )

20= v-( 7 )

27= v

Step-by-step explanation:

Adding a negative is the sane as subtracting. Add like terms. Add 7 to both sides. 27= v

8 0
3 years ago
Find the circumference of the circle
vaieri [72.5K]

Answer:

72.22

Step-by-step explanation:

4 0
3 years ago
Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
2 years ago
Use the distributive property to simplify the expression 5 ( − 1 x − 6 + 6 y )
expeople1 [14]

Answer:

the answer should be -5x - 30 + 30 y

3 0
3 years ago
Read 2 more answers
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