If you toss a coin and let it fall to the floor what is the probability it lands with heads face up

Mathematics

1 answer:

Marat540 [252]2 years ago

5 0

Answer:

1/2

Step-by-step explanation:

PROBABILITY: THE LIKELIHOOD OF AN EVENT.

When you toss a coin, there are only two outcomes: heads or tails.

Therefore, the probability of the coin landing face-up would be 1 in 2 or 1/2.

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Flauer [41]

Answer:

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Step-by-step explanation:

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1 year ago

Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form

almond37 [142]

Answer:

$=14a^5+14a^4-10a^3-16a$

Step-by-step explanation:

$\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4$

$\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a$

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2 years ago

C=-7/15 and x=2/5 c-4x write your answer in simplest form

pogonyaev

9514 1404 393

Answer:

-31/15

Step-by-step explanation:

Put the numbers in the expression and do the arithmetic.

$c-4x=-\dfrac{7}{15}-4\cdot\dfrac{2}{5}=-\left(\dfrac{7}{15}+\dfrac{8}{5}\right)\\\\=-\left(\dfrac{7}{15}+\dfrac{24}{15}\right)=\boxed{-\dfrac{31}{15}}$