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3 years ago

Explain the method to decrease friction?

Chemistry

2 answers:

Nookie1986 [14]3 years ago

5 0

Answer:

having a smooth or lubricated surface may help decrease friction.

Explanation:

nlexa [21]3 years ago

5 0

Have a smooth surface i did this before hope helps

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Sulfur undergoes combustion to yield sulfur trioxide by the following reaction equation:

12345 [234]

Answer:

Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J

Explanation:

Given reaction: 2S + 3O₂ → 2 SO₃

Given: The enthalpy of reaction: ΔH = - 792 kJ

Given mass of S: w₂ = 42.8 g, Molar mass of S: m = 32 g/mol

In the given reaction, the number of moles of S reacting: n = 2

As, Number of moles: $n = \frac{mass\: (w_{1})}{molar\: mass\: (m)}$

∴ mass of S in 2 moles of S: $w_{1} = n \times m = 2\: mol \times 32\: g/mol = 64\: g$

Given reaction: 2S + 3O₂ → 2 SO₃

In this reaction, the limiting reagent is S

⇒ 2 moles S produces (- 792 kJ) heat.

or, 64 g of S produces (- 792 kJ) heat.

∴ 42.8 g of S produces (x) amount of heat

⇒ The amount of heat produced by 42.8 g S:

$x = \frac{(- 792\: kJ) \times 42.8\: g}{64\: g} = (-529.65)\: kJ$

$\Rightarrow x = (-5.2965 \times 10^{2})\: kJ = (-5.2965 \times 10^{5})\: J$

$(\because 1 kJ = 10^{3} J)$

Therefore, the amount of heat produced by the reaction of 42.8 g S = (-5.2965 × 10²) kJ = (-5.2965 × 10⁵) J

8 0

3 years ago

How much momentum does a 200 kg rhino have that is running at 35 m/s E

nirvana33 [79]

Answer:

7000 kg*m/s E

Explanation:

Momentum formula: p=mv

m=200kg

v=35 m/s East

p=(200kg)(35m/s E)

m=7000 kg*m/s E

If you want to simplify it further, m=7*10^3 kg*m/s E

5 0

2 years ago

Read 2 more answers

how many grams of potassium chloride, KCL(molar mass is 74.55g/mol) are produced if 25 grams of potassium chlorate KClo^3 decomp

JulsSmile [24]

Answer:

Mass = 15.20 g of KCl

Explanation:

The balance chemical equation for the decomposition of KClO₃ is as follow;

2 KClO₃ = 2 KCl + 3 O₂

Step 1: Calculate moles of KClO₃ as;

Moles = Mass / M/Mass

Moles = 25.0 g / 122.55 g/mol

Moles = 0.204 moles

Step 2: Find moles of KCl as;

According to equation,

2 moles of KClO₃ produces = 2 moles of KCl

So,

0.204 moles of KClO₃ will produce = X moles of KCl

Solving for X,

X = 2 mol × 0.204 mol / 2 mol

X = 0.204 mol of KCl

Step 3: Calculate mass of KCl as,

Mass = Moles × M.Mass

Mass = 0.204 mol × 74.55 g/mol

Mass = 15.20 g of KCl

6 0

3 years ago

Noble gas compounds like KrF, XeCl, and XeBr are used in excimer lasers. Draw an approximate molecular orbital diagram appropria

Aneli [31]

Answer:

Here's what I get.

Explanation:

The MO diagrams of KrBr, XeCl, and XeBr are shown below.

They are similar, except for the numbering of the valence shell orbitals.

Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.

However, the MO diagrams are approximately correct.

The ground state electron configuration of KrF is

$(1\sigma_{g})^{2}\, (1\sigma_{u}^{*})^{2} \, (2\sigma_{g})^{2} \, (2\sigma_{u}^{*})^{2} \, (3\sigma_{g})^{2} \, (1\pi_{u})^{4} \, (1\pi_{g}^{*})^{4} \, (3\sigma_{g}^{*})^{1}$

KrF⁺ will have one less electron than KrF.

You remove the antibonding electron from the highest energy orbital, so the bond order increases.

The KrF bond will be stronger.

6 0

3 years ago

A sample of gas is collected in a flask with a volume of 267 mL at a pressure of 771 mmHg and a temperature of 21C. If the mass

nadya68 [22]

Answer:

M=93.5g/mol

Explanation:

I did this in class and it was a review. :)

6 0

2 years ago