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Eddi Din [679]
3 years ago
10

How is the periodic law demonstrated in halogens

Chemistry
2 answers:
Zina [86]3 years ago
4 0

Answer:

The periodic law demonstrated in halogens by:

All halogens have the same number of valence electrons and similar chemical properties

Explanation:

  • The halogen are located in the group of seven A of the periodic table example of halogen are iodine and chlorine.
  • The halogens are the reactive non-metals in the periodic table, it reacts with alkali metals.
  • Halogen responds with iron, iron wool outbreak into flames when it responds with fluorine gas.
  • Halogen range from solid to liquid to gaseous at room temperature.

inn [45]3 years ago
3 0
Halogens is defined as the group of 7 periodic table. As, every periodic table contains 7 valence electrons and they only need 1 more to complete an outer shell, that is why they are extremely reactive. And according to the law that recurring patterns of the properties of elements arise when they are arranged in order of increasing atomic number. As the halogen all act very similarly with each other in chemical reaction, it is true.
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In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) ⇌
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Answer: Equilibrium constant is 0.70.

Explanation:

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equilibrium concentration of CO=\frac{moles}{volume}=\frac{0.18moles}{1L}=0.18M [/tex]

The given balanced equilibrium reaction is,

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Initial conc.            0.35 M       0.40M       0     0

At eqm. conc.    (0.35-x) M   (0.40-x) M   (x) M    (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO_2]\times [H_2O]}{[CO]\times [H_2O]}

K_c=\frac{x\times x}{(0.40-x)(0.35-x)}

we are given : (0.35-x)= 0.18

x = 0.17

Now put all the given values in this expression, we get :

K_c=\frac{0.17\times 0.17}{(0.40-0.17)(0.35-0.17)}

K_c=0.70

Thus the value of the equilibrium constant is 0.70.

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3 years ago
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