A. 1.01 is the right answer
Since
The formula is Pv= nRT
P=1 atm
V= 22.4 L
N= x
r= 0.0821
t = 273 k (bc it’s standard temperature)
So (1)(22.4)=(x)(0.0821)(273)
X= 1.001
Answer:
Veja, por exemplo, que os elementos mais eletronegativos são os que estão no canto superior direito da tabela, isto é, o flúor (4,0) e o oxigênio (3,5), e os menos eletronegativos são os que estão no canto inferior esquerdo, que são o frâncio (0,8) e o césio (0,8).
Explanation:
Answer:
The difference in electronegativity between fluorine (4.0) and hydrogen (2.1) is quite high, so the shared electrons spend much more time in the vicinity of the fluorine atom. As a result, fluorine carries a partial negative charge in this molecule, whereas hydrogen carries a partial positive charge
Explanation:
I believe the answer to your question would be Fluorine. I hope I answered your question, my friend. :)
Answer:
Calculate the pH of 0.010 M HNO2 solution. The K, for HNO2 is 4.6 x 104
Answer: pH = 2.72