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Ne4ueva [31]
3 years ago
7

Describe the contributions made by Oparin, Haldane, Miller, and Urey toward understanding the origin of organic molecules.

Chemistry
1 answer:
balu736 [363]3 years ago
8 0

Answer:

The theory of Oparin and Haldane was based on the fact that the primitive atmosphere was very different from the current atmosphere, since energy was abundant on the young planet. Both proposed that the appearance of life was preceded by a period they called "chemical evolution."

On the other hand, Miller Urey made an experiment where it was shown that some organic components were formed spontaneously if they were simulating the conditions of the Earth's early atmosphere.

Explanation:

The first hypotheses about the origin of life on Earth were suggested by Oparin and Haldane, who worked independently. Oparin presented his ideas on the origin of life in the year of 1922 by publishing them in the year of 1924. For his part, Haldane published similar ideas in 1929, however, Haldane gave priority to Oparin in the formulation of the theory.

Oparin based his hypotheses using a model he called "coacervates", which are colloidal systems formed by macromolecules that formed in aqueous media and would have evolved to form cells with membranes. According to Oparin, living beings modified the primitive atmosphere and this would have prevented, the formation of life from inorganic substances.

The Miller and Urey experiments helped reinforce the theory that the first way of life was created spontaneously through chemical reactions. However, there are still many scientists who are not convinced.

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For a certain chemical reaction, the standard Gibbs free energy of reaction at 30.0 °C is 110. kJ. Calculate the equlilibriunm c
mestny [16]

Answer:

Explanation:

The equation that relates standard Gibbs free energy, ΔG, with equilibrium constant, K, is:

ΔG = -RT ln K

<em>Where R is gas constant, 8.314J/molK, and T is absolute temperatue (30.0°C + 273.15 = 303.15K).</em>

<em />

Replacing (110kJ = 110000J):

110000J/mol = -8.314J/molK*303.15K ln K

-43.644 = lnK

1.11x10⁻¹⁹ = K

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7 0
3 years ago
The oxygen atom is smaller than the sulfur atom because _____(1) the outer electrons of oxygen are more effectively screened fro
Romashka [77]

Answer: Option (2) is the correct answer.

Explanation:

Atomic number of oxygen atom is 8 and its electronic distribution is 2, 6. So, it contains only 2 orbitals which are closer to the nucleus of the atom.

As a result, the valence electrons are pulled closer by the nucleus of oxygen atom due to which there occurs a decrease in atomic size of the atom.

Whereas atomic number of sulfur is 16 and its electronic distribution is 2, 8, 6. As there are more number of orbitals present in a sulfur atom so, the valence electrons are away from the nucleus of the atom.

Hence, there is less force of attraction between nucleus of sulfur atom and its valence electrons due to which size of sulfur atom is larger than the size of oxygen atom.

Thus, we can conclude that the oxygen atom is smaller than the sulfur atom because the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.

3 0
3 years ago
Panuto: Punan ang talaan sa ibaba at suriing mabuti ang sarili upang higit mong
Novay_Z [31]
The answer is 2

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4 0
3 years ago
Select correct examples of linear molecules for five electron groups. Select correct examples of linear molecules for five elect
Shalnov [3]

Explanation:

Formula to calculate hybridization is as follows.

                Hybridization = \frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

So, hybridization of BeCl_{2} is as follows.

              Hybridization = \frac{1}{2}[V + N - C + A]

                                    = \frac{1}{2}[2 + 2]

                                    = 2

Hybridization of BeCl_{2} is sp. Therefore, BeCl_{2} is a linear molecule. There will be only two electron groups through which Be is attached.

Similarly, hybridization of XeF_{2} is calculated as follows.

         Hybridization = \frac{1}{2}[V + N - C + A]

                                    = \frac{1}{2}[8 + 2]

                                    = 5

Therefore, hybridization of XeF_{2} is sp^{3}d. Therefore, [tex]XeF_{2} is also a linear molecule. Though there are three lone pair of electrons present on a xenon atom and it is further attached with fluorine atoms through two electron pairs. Hence, there are in total five electron groups.

Thus, we can conclude that out of the given options XeF_{2} is the correct examples of linear molecules for five electron groups.

7 0
3 years ago
The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is
Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

6 0
3 years ago
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