Answer:
the answer is 1:3:2
Hope this helps, let me know if you need any other help, Stoichiometry is hard
Answer : The equilibrium constant for this reaction is, 
Explanation :
The given main chemical reaction is:
; 
The intermediate reactions are:
(1)
; 
(2)
; 
We are reversing reaction 1 and multiplying reaction 2 by 2 and then adding both reaction, we get:
(1)
; 
(2)
; 
Thus, the equilibrium constant for this reaction will be:


Thus, the equilibrium constant for this reaction is, 
<span>Get into moles first. .0590 grams over 540.8 grams per mole = 1.09 x l0^-4 moles
Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq)
Ksp = (Sr++)^3(As04^-3)^2
(Sr++) = 3 X l.09 x l0^-4 = 3.27 x l0^-4
(As04^-3) = 2 x l.09 x l0^-4 = 2.18 x l0^-4
<span>Ksp = (3.27 x l0^-4)^3 (2.18 x l0^-4)^2 which equals 1.66 x 10^-18th
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