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AfilCa [17]
4 years ago
6

In which biome would you most likely find plants that grow far apart from one another, with narrow leaves and shallow roots? Why

do these plants have these adaptions?
Please help!?
Chemistry
2 answers:
mr Goodwill [35]4 years ago
8 0

Answer: Answer. A plant with narrow leaves and shallow roots would probably be found in the desert, where there is not a lot of water.

Explanation:

alexdok [17]4 years ago
8 0

Answer:

A plant with narrow leaves and shallow roots would probably be found in the desert, where there is not a lot of water. Narrow leaves help prevent water loss.

Explanation:

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Dimas [21]

Answer:

The first ionization energy is the energy it takes to remove an electron from a neutral atom.

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8 0
3 years ago
Write the molecular formula of nitrate using criss cross method <br><br><br><br>​
exis [7]

Answer:

NO3 that is the answer to the question

8 0
3 years ago
Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g) K=0.042 The concentrations of the products at equilibrium are [PCl3]=0.18 M and
tatyana61 [14]

<u>Answer:</u> The equilibrium concentration of PCl_5 is 1.285 M.

<u>Explanation:</u>

The chemical equation for the decomposition of phosphorus pentachloride follows:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)

The expression for equilibrium constant is given as:

K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}

We are given:

K_c=0.042

[PCl_3]=0.18M

[Cl_2]=0.30M

The concentration of solid substances are taken to be 1. Thus, they do not appear in the equilibrium constant expression.

Putting values in above equation, we get:

0.042=\frac{0.18\times 0.30}{[PCl_5]}

[PCl_5]=1.285

Hence, the equilibrium concentration of PCl_5 is 1.285 M.

6 0
3 years ago
How many grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate?
Korvikt [17]

Answer: There is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

Explanation:

Chemical equation depicting reaction between sodium phosphate and aluminum carbonate is as follows.

Al_{2}(CO_{3})_{3} + 2Na_{3}PO_{4} \rightarrow 2AlPO_{4} + 3Na_{2}CO_{3}

As this equation contains same number of atoms on both reactant and product side. So, this equation is a balanced equation.

According to the equation, 2 moles of sodium phosphate is giving 3 moles of sodium carbonate.

Therefore, sodium carbonate formed by 5.3 moles of sodium phosphate is as follows.

\frac{3}{2} \times 5.3 mol\\= 7.95 mol

As number of moles is the mass of substance divided by its molar mass. So, mass of sodium carbonate ( molar mass = 105.98 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\7.95 mol = \frac{mass}{105.98 g/mol}\\mass = 842.54 g

Thus, we can conclude that there is 842.54 grams of sodium carbonate are produced when 5.3 moles of sodium phosphate reacts with aluminum carbonate.

8 0
3 years ago
Please help me please
Ludmilka [50]

Answer:

b

Explanation:

i read this once and remember,trust me!

7 0
3 years ago
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