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AfilCa [17]
4 years ago
6

In which biome would you most likely find plants that grow far apart from one another, with narrow leaves and shallow roots? Why

do these plants have these adaptions?
Please help!?
Chemistry
2 answers:
mr Goodwill [35]4 years ago
8 0

Answer: Answer. A plant with narrow leaves and shallow roots would probably be found in the desert, where there is not a lot of water.

Explanation:

alexdok [17]4 years ago
8 0

Answer:

A plant with narrow leaves and shallow roots would probably be found in the desert, where there is not a lot of water. Narrow leaves help prevent water loss.

Explanation:

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Changes in a species over long periods of time are called
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These are known as adaptions which causes evolution 
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Which element would have a full outer shell of electrons if it gained three electrons?
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Answer:

Octet Rule is defined as the chemical rule in which atoms tend to form bonds in such a way that it completes its valence shell or tend to achieve the configuration of a noble gas.

Explanation:

The lithium is chemical element, which has atomic number 3. It has one valence electron in its outermost shell, therefore, it will require 7 more electrons to complete its octet.

The element nitrogen has the atomic number 7, such that it has 5 valence electrons in its outer most shell. Therefore, it will require 3 more electrons to complete its octet.

The noble gas Argon have complete octet, such that it does not require any electrons to complete its octet. the gas is inert and non-reactive.

The chemical element Boron has atomic number 5, such that it has three electrons in its outer most shell. Therefore, it will require 5 more electrons to complete its octet.

Hence, the correct option is Nitrogen.

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Explain the reason that maps must change over time
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Explanation:

Because the place on the map can be changed to another shape by natural effects like faulting,folding , volcanism

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Briefly explain why an unbalanced chemical equation cannot fully describe a reaction?
zubka84 [21]

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5 0
3 years ago
5. What are the relative rates of diffusion for methane, CH, and oxygen, O2? If O2 la travels 1.00 m in a certain amount of time
11Alexandr11 [23.1K]

Answer:

The relative rates of diffusion for methane and oxygen is 1.4142.

Methane gas will be able to travel 1.4142 meter in the same conditions.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. Mathematically written as:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

We are given:

Molar mass of methane gas, m = 16 g/mol

Molar mass of oxygen gas,m' = 32 g/mol

By taking their ratio, we get:

\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{m'}{m}}

\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{32}{16}}=1.4142

The relative rates of diffusion for methane and oxygen is 1.4142.

If oxygen gas travels 1 meters in time t.

Rate of diffusion of oxygen =d_{O_2}=\frac{1 m}{t}

If methane gas travels travels in y meters in time t.

Rate of diffusion of methane=d_{CH_4}=\frac{y }{t}

\frac{d_{CH_4}}{d_{O_2}}=\frac{\frac{y }{t}}{\frac{1 m}{t}}=1.4142

y = 1.4142 m

Methane gas will be able to travel 1.4142 meter in the same conditions.

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3 years ago
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