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guapka [62]
4 years ago
6

A car is traveling at 20 minutes/second and is brought to rest by applying brakes over a period of 4 seconds.What is it average

acceleration over this time interval?
Chemistry
1 answer:
Neporo4naja [7]4 years ago
5 0

-5m/s

Explanation:

Given parameters:

Speed of the car = 20m/s

Time taken = 4s

Unknown:

Average acceleration = ?

Solution:

Acceleration is the change in velocity or speed with time of a body.

  Acceleration = \frac{v - u}{t}

 v is the final velocity = 0

 u is the initial velocity

 t is the time

Input the values:

   Acceleration = \frac{0-20}{4}  = -5m/s

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

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Answer:

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8 0
3 years ago
1. What type of reaction is listed below? Prove that it is balanced by listing the number of elements on both side of the equati
ohaa [14]
Is there a mistake or am i doing something wrong  
6 0
3 years ago
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Coke is an impure form of carbon that is often used in the in- dustrial production of metals from their oxides. If a sample of c
steposvetlana [31]

Answer:

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

Explanation:

2CuO+C\rightarrow 2Cu+CO_2

1 Ton = 907185 grams

Mass of copper oxide = 1.0 Ton = 907185 grams

Moles of copper oxide =\frac{907185 g}{79.55 g/mol}=11,403.95 moles

According to reaction, 2 moles of copper oxide reacts with 1 mole of carbon.

Then 11403.95 moles of copper oxide will react with:

\frac{1}{2}\times 11403.95 mol=5,701.98 mol of carbon

Mass of 5,701.98 moles of carbon:

5,701.98 mol\times 12 g/mol=68,423.75 g

Mass of coke = x

Mass of carbon = 68,423.75 g

Percentage of carbon in coke = 95%

95\%=\frac{68,423.75 g}{x}\times 100

x=720,250.09 g=0.794 Ton

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

3 0
3 years ago
From the balanced reaction:
Lelu [443]

Answer:

The mass of O₂ that will be needed to burn 36.1 g B₂H₆ is 125.29 g.

7 0
3 years ago
The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to
tigry1 [53]

Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of CuFeS_2 = 183.511 g/mole

  • First we have to calculate the moles of Cu.

\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

The moles of Cu = 4.7209 moles

From the given chemical formula, CuFeS_2 we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of CuFeS_2 = 4.4209 moles

  • Now we have to calculate the mass of CuFeS_2.

Mass of CuFeS_2 = Moles of CuFeS_2 × Molar mass of CuFeS_2 = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of CuFeS_2 = 866.337 g = 0.8663 Kg         (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.


3 0
3 years ago
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