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Otrada [13]
2 years ago
6

Please help numbers 1 through 5.

Mathematics
1 answer:
ser-zykov [4K]2 years ago
4 0

Answer:

i can't see

Step-by-step explanation:

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JOJO help me I can't work good
photoshop1234 [79]

Answer:

C. 46 degrees

Step-by-step explanation:

In a rotation all angles and side lengths are preserved so the angle measure will be the same in both the image and pre-image.

6 0
3 years ago
Read 2 more answers
What is the distance between the points (59.5, 34.2) and (15.3, 14.9)? Enter your answer rounded to the nearest tenth (0.1).
nirvana33 [79]

Answer:

48.2

Step-by-step explanation:

√(x2-x1)²+(y2-y1)²

√(15.3-59.5)² +(14.9-34.2)²

√(-44.2)² + (-19.3)²

√1953.64+372.49

√2326.13

48.2

5 0
2 years ago
Read 2 more answers
The estimated quotient of 895 divided by 19 is what number?a. 40 b. 45 c. 55 d. 60
Ira Lisetskai [31]

Answer:

b. 45

Step-by-step explanation:

895 ÷ 19 = 47.1

47.1 rounded is 50, but since there is no 50 option, we'll just round it down to 45.

--

another way:

round 895 (900) and 19 (20)

divide:

895 ÷ 20 = 45

you'll get 45 either way :)

7 0
2 years ago
(Urgent)!<br> Fill in the blank with the correct response.<br><br> Find x<br> x = _____________
Kruka [31]

Answer:

4

similar right triangles

\frac{8}{x}  = \frac{x}{2}

x^{2}  = 16\\x=4

Step-by-step explanation:

6 0
2 years ago
If(√14/√7-2)-(√14/√7+2)=a√7+b√2 find the values of a and b where a and b are rational numbers​
seraphim [82]

Answer:

  • a = 4/3 and b = 0

============================

<h2>Given expression:</h2>

\dfrac{\sqrt{14} }{\sqrt{7}-2} -\dfrac{\sqrt{14} }{\sqrt{7}+2}

<h2>Simplify it in steps:</h2>

<h3>Step 1</h3>

Bring both fractions into common denominator:

\dfrac{\sqrt{14} (\sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} - \dfrac{\sqrt{14} (\sqrt{7}-2)}{(\sqrt{7}-2)(\sqrt{7}+2)}

<h3>Step 2</h3>

Simplify:

\dfrac{\sqrt{14} ((\sqrt{7}+2) - (\sqrt{7}-2))}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{\sqrt{14} (\sqrt{7}+2 - \sqrt{7}+2)}{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7}-2)(\sqrt{7}+2)} =

\dfrac{4\sqrt{14} }{(\sqrt{7})^2-2^2} =

\dfrac{4\sqrt{14} }{7-4} =

\dfrac{4}{3}  \sqrt{14} }

<h3>Step 3</h3>

Compare the result with given expression to get:

  • a = 4/3 and b = 0

4 0
2 years ago
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