<17 and <18 are vertical angles. m <17=(5x+3)(degrees) and m<18=(3x+23)(degrees) find the measure of <18

Find the missing sides.

love history [14]

Answer:

Part 3)

$x=6\ units$

$y=3\ units$

Part 4) $x=18\sqrt{2}\ units$

Step-by-step explanation:

Part 3)

step 1

Find the value of x

In the right triangle of the figure we know that

The cosine of angle of 30 degrees is equal to the adjacent side to angle of 30 degrees divide by the hypotenuse

so

$cos(30\°)=\frac{3\sqrt{3}}{x}$

and remember that

$cos(30\°)=\frac{\sqrt{3}}{2}$

substitute

$\frac{\sqrt{3}}{2}=\frac{3\sqrt{3}}{x}$

Simplify

$x=(2*3)=6\ units$

step 2

Find the value of y

In the right triangle of the figure we know that

The sine of angle of 30 degrees is equal to the opposite side to angle of 30 degrees divide by the hypotenuse

so

$sin(30\°)=\frac{y}{x}$

and remember that

$sin(30\°)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{y}{6}$

$y=6/2=3\ units$

Part 4) Find the value of x

Applying the Pythagoras Theorem

$x^{2} =18^{2} +18^{2} \\ \\x^{2} = 324+324\\ \\x^{2}=648\\ \\x=\sqrt{648}\ units$

Simplify

$x=18\sqrt{2}\ units$

6 0

2 years ago

Please HELP QUICK!!!!!!!!!!!!!!!!!!

aleksklad [387]

Answer:

so the answer is 0.2

1/5 = 0.2

5 0

2 years ago

To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil

Fiesta28 [93]

Answer:

The sample has not met the required specification.

Step-by-step explanation:

As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow

$H_0$ : The true average penetration is 50 mils

$H_a$ : The true average penetration is > 50 mils

Since we are trying to see if the true average is greater than 50, this is a right-tailed test.

If the level of confidence is α = 0.05 then the $z_\alpha$ score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)

The z-score associated with this test is

$z=\frac{\bar x-\mu}{s/\sqrt{n}}$

where

$\bar x$ = mean of the sample

$\mu$ = average established by the specification

s = standard deviation of the sample

n = size of the sample

Computing this value of z we get z = 3.42

Since z > $z_\alpha$ we can conclude that the sample has not met the required specification.

5 0

3 years ago

The universal set in this diagram is the set of integers from 1 to 15. Place the integers in the correct place in the venn diagr

alexira [117]

Answer:

The universal set in this diagram is the set of integers from 1 to 15. Place the integers in the correct place in the venn diagram

Step-by-step explanation:

this is the answer

5 0

1 year ago

Natalie made a nut mixture that contains

Harman [31]

Answer:

50%

Step-by-step explanation:

10 kg of mixed nuts that contain 60% peanuts

60(10)

plus

15 kg of a different brand of mixed nuts. with x% peanuts

x(15)

=

That makes 25 kg with 54% peanuts

54(25)

--------------------------

Equation

60(10) + x(15) = 54(25)

600 + 15x = 1350

Subtract 600 from both sides

15x = 750

Diviede both sides by 15

x = 50

50%

4 0

2 years ago