The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:
Expand the function
Reorder the terms
Factor the expression
Factor out x -1
Expand
Factorize
](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Bx%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%5D%28x%20-%201%29)
Factor out x + 2
The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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Answer:
I think it's -2
Step-by-step explanation:
Answer:
(0,−4)
Step-by-step explanation:
Answer:
the day that immediately proceeds the last and final spring sabbat, ... The fact that Beltane and Samhain happen in unison twice a year lends
Step-by-step explanation:
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➷ The range is the highest value minus the smallest value
Therefore, you just need to subtract the two values to find the values:
-2 - 4 = -6
The difference is just 6, so your answer is C. 6
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