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stira [4]
2 years ago
6

Without using a calculator, determine the number of real zeros of the function

Mathematics
1 answer:
kumpel [21]2 years ago
3 0

The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3

<h3>How to determine the number of real zeros?</h3>

The equation of the function is given as:

f(x) = x^3 + 4x^2 + x - 6

Expand the function

f(x) = x^3 + 5x^2 - x^2 + 6x - 5x - 6

Reorder the terms

f(x) = x^3 + 5x^2 + 6x - x^2 - 5x - 6

Factor the expression

f(x) = x(x^2 + 5x + 6) -1(x^2 + 5x + 6)

Factor out x -1

f(x) = (x^2 + 5x + 6)(x -1)

Expand

f(x) = (x^2 + 3x + 2x + 6)(x -1)

Factorize

f(x) = [x(x + 3) + 2(x + 3)](x - 1)

Factor out x + 2

f(x) = (x + 3)(x + 2)(x- 1)

The function has been completely factored and it has 3 linear factors

Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3

Read more about functions at:

brainly.com/question/7784687

#SPJ1

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Find the general solution of (x+3)y’=2y
gregori [183]

Answer:

y=C(x+3)^2

Step-by-step explanation:

We are given:

\displaystyle (x+3)y^\prime=2y

Separation of Variables:

\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}

So:

\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx

Integrate:

\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx

Integrate:

\displaystyle \ln|y|=2\ln|x+3|+C

Raise both sides to e:

|y|=e^{2\ln|x+3|+C}

Simplify:

|y|=(e^{\ln|x+3|})^2\cdot e^C

So:

|y|=C|x+3|^2

Simplify:

y=\pm C(x+3)^2=C(x+3)^2

5 0
3 years ago
In rectangle ANGL, AN = 16 and AG = 34. Find the perimeter of ANGL.
Viktor [21]
In a rectangle, opposite sides are equal so you can multiply the side lengths by 2 and add them so 16(2)+34(2) and yu get 32+68. The perimeter is 100
8 0
3 years ago
Read 2 more answers
Marion Pelk worked 9 days in two weeks. He worked each day and was paid $7.1 an hour. What gross pay he earn for the two weeks?
Andrews [41]

Answer:

$1533.60 !

Step-by-step explanation:

$7.10 per hour needs to be times by 24 (to calculate the pay per day) = $170.40 then times that by 9 = $1533.60 (The pay for 9 days which is coincidently the pay per 2 weeks!

Job done! The answer is $1533.60!

[If I am wrong please message me and tell me]

5 0
3 years ago
Can anyone help me please
Nady [450]

Yo sup??

since WY is the perpendicular bisector we can say

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ElenaW [278]
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