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3 years ago

14

4+√5 /4-√5 +4-√5/4+√5

1 answer:

jek_recluse [69]3 years ago

6 0

Answer: 8

Step-by-step explanation: since two opposites add up to zero, remove them from the expression. This simplifies to 4 + 4 which equals 8.

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Fill in the two missing boxes?

guapka [62]

Answer:

no

Step-by-step explanation:

thanks for 5 points

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4 years ago

The sum of eighteen and five times a number is the same as twice the number

FrozenT [24]

Yes it the same number

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4 years ago

A furnace is rated 4000 BTU per hour. How many foot pounds of energy are released in one hour?

Kipish [7]

To solve this we are going to use a conversion factor. We know that 1 BTU per hour is approximately 778 foot-pounds of energy per hour, so our conversion factor will be: $\frac{778foot-pound}{1BTU}$ .

Now we just need to multiply <span>4000 BTU by our conversion factor:
</span> $4000BTU*\frac{778foot-pound}{1BTU}=3112000foot-pound$
<span>
We can conclude that the furnace released </span><span>3,112,000 foot pounds of energy in one hour.</span>

4 0

3 years ago

Si "m" es el lado mayor de un triángulo, dos cuyos ángulos interiores miden 30° y 60°, entonces el perímetro del triángulo es

lions [1.4K]

Answer:

$perimetro = \dfrac{(3 + \sqrt{3})m}{2}$

Step-by-step explanation:

triángulo 30°-60°-90°

$1~:~\sqrt{3}~:~2$

$1m~:~m\sqrt{3}~:~2m$

$\dfrac{m}{2}~:~\dfrac{m\sqrt{3}}{2}~:~m$

$perimetro = \dfrac{m}{2} + \dfrac{m\sqrt{3}}{2} + m$

$perimetro = \dfrac{m}{2} + \dfrac{m\sqrt{3}}{2} + \dfrac{2m}{2}$

$perimetro = \dfrac{m + m\sqrt{3} + 2m}{2}$

$perimetro = \dfrac{3m + m\sqrt{3}}{2}$

$perimetro = \dfrac{(3 + \sqrt{3})m}{2}$

7 0

3 years ago

Which expressions are equivalent to \dfrac{4^{-3}}{4^{-1}} 4 −1 4 −3 start fraction, 4, start superscript, minus, 3, end super

Slav-nsk [51]

Answer:

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}$

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}$

Step-by-step explanation:

Given

$\dfrac{4^{-3}}{4^{-1}}$

Required

Choose equivalent expressions

Choosing the first answer:

$\dfrac{4^{-3}}{4^{-1}}$

Split expressions

$4^{-3} * \frac{1}{4^{-1}}$

Apply laws of indices: $(a^{-b} = \frac{1}{a^b})$

$\frac{1}{4^3} * \frac{1}{4^{-1}}$

Apply laws of indices: $(a^{-b} = \frac{1}{a^b})$

$\frac{1}{4^3} * \frac{1}{1/4}$

$\frac{1}{4^3} * \frac{4^1}{1}$

$\frac{4^1}{4^3}$

Hence:

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}$

Choosing the second:

$\dfrac{4^{-3}}{4^{-1}}$

Apply law of indices: $(\frac{a^m}{a^n} = a^{m-n})$

So,

$\dfrac{4^{-3}}{4^{-1}} = 4^{-3-(-1)}$

$\dfrac{4^{-3}}{4^{-1}} = 4^{-3+1)}$

$\dfrac{4^{-3}}{4^{-1}} = 4^{-2}$

Apply law of indices: $(a^{-b} = \frac{1}{a^b})$

So:

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}$

4 0

3 years ago