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3 years ago

What is the correct definition of solution?

Physics

1 answer:

STALIN [3.7K]3 years ago

4 0

B.a homogeneous mixture

A solution is a homogeneous mixture of two or more substances. The amount of solute that can be dissolved in solvent is called its solubility.

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What sauce goes best with chicky nuggies

Sever21 [200]

Answer:

honey mustard or chick fil a sauce their special sauce

Explanation:

6 0

3 years ago

The work energy principle states that the change in kinetic energy of an object is equal to the net work done on the object. If

sattari [20]

Answer:

$v=\sqrt{2gh}\ m/s$

Explanation:

From work energy theorem

Work done by all forces = Change in kinetic energy

Lets take

m= mass of object

h=height from the ground surface

initial velocity of object = 0 m/s

The final velocity of object is v

Work done by gravitational force = m g . h

The final kinetic energy = 1/2 m v²

Work done by all forces = Change in kinetic energy

m g h = 1/2 m v² - 0

v² = 2 g h

$v=\sqrt{2gh}\ m/s$

6 0

4 years ago

Calculate the power transfer when a pump moves 50kg of water through a vertical height of 8meters in 5seconds (take g =10meters

Vika [28.1K]

Hi there!

Recall the following relationships:

$W = \Delta U = mg\Delta h\\\\P = \frac{W}{t}$

W = Work (J)

U = Potential Energy (J)

m = mass (kg)

g = acceleration due to gravity (9.8 m/s²)

h = height (m)

t = time (s)

Begin by calculating the work:

$W = 50(10)(8) = 4000 J$

Now, divide by the time to solve for power:

$P = \frac{4000}{5} = \boxed{800W}$

**W is the unit for power (Watts). Be careful not to get the two confused.

4 0

3 years ago

Professor Sanchez believes that children acquire language through reinforcement from adults, especially their parents. He believ

MArishka [77]

The answer is “behaviorist”

4 0

3 years ago

A beam of alpha particles ( q = +2e, mass = 6.64 x 10-27 kg) is accelerated from rest through a potential difference of 1.8 kV.

Mrrafil [7]

Answer:

The magnetic field required required for the beam not to be deflected is $B = 0.0036T$

Explanation:

From the question we are told that

The charge on the particle is $q = +2e$

The mass of the particle is $m = 6.64 *10^{-27} kg$

The potential difference is $V_a = 1.8 kV = 1.8 *10^{3} V$

The potential difference between the two parallel plate is $V_b = 120 V$

The separation between the plate is $d = 8 mm = \frac{8}{1000} = 8*10^{-3}m$

The Kinetic energy experienced by the beam before entering the region of the parallel plate is equivalent to the potential energy of the beam after the region having a potential difference of 1.8kV

$KE_b = PE_b$

Generelly

$KE_b = \frac{1}{2} m v^2$

And $PE_b = q V_a$

Equating this two formulas

$\frac{1}{2} mv^2 = q V_a$

making v the subject

$v = \sqrt{\frac{q V_a}{2 m} }$

Substituting value

$v = \sqrt{\frac{ 2* 1.602 *10^{-19} * 1.8 *10^{3}}{2 * 6.64 *10^{-27}} }$

$v = 41.65*10^4 m/s$

Generally the electric field between the plates is mathematically represented as

$E = \frac{V_b}{d}$

Substituting value

$E = \frac{120}{8*10^{-3}}$

$E = 15 *10^3 NC^{-1}$

the magnetic field is mathematically evaluate

$B = \frac{E}{v}$

$B = \frac{15 *10^{3}}{41.65 *10^4}$

$B = 0.0036T$

6 0

3 years ago