Weight of the barbell W = 200 Ndistance of the joint is r = 40 cm = 0.4 mtorque created by the weight at the joint is τ = F*r = 200 N*0.4 m = 80 N.mat equilibrium condition , Στ = force*distance - 80 N.m = 0 F'*0.4 - 80 N.m = 0 F'*0.4 = 80 force F' = 200 N
Answer:
12.24 m/s
Explanation:
Speed: This can be defined as the rate of change of distance with time. The S.I unit of speed is m/s.
Using the formula,
a = v/t................ Equation 1
Where a = acceleration of the sprinter, v = speed of the sprinter, t = time.
making v the subject of the equation,
v = at ................. Equation 2
Given: a = 5.1 m/s², t = 2.4 s.
Substitute into equation 2
v = 5.1(2.4)
v = 12.24 m/s.
Hence, the speed of the sprinter = 12.24 m/s
Explanation:
Let 
and 
The sum of the two vectors is
The difference between the two vectors can be written as
Answer:
cells are the things that u are made of
Explanation:
the relationship between cells and organisms is that cells make up organisms and without cells we would not be here
<h2><u><em>
hope this helps plz mark as brainliest</em></u></h2>
Answer:
e. 2ωs / √5
Explanation:
The rotational kinetic energy of any rigid body, like an extension of the translational kinetic energy, is defined as follows:
Krot = 1/2 *I * ω²
For a solid sphere of mass M and radius R, the moment of inertia regarding any axis through its center, is as follows:
I =2/5 M*R²⇒ Krot(sp) = 1/2 (2/5 M*R²)*ωs² (1)
For a solid cylinder, rotating through an axis running through the central axis of the cylinder, the moment of inertia can be calculated as follows:
I = 1/2 M*R² ⇒ Krot(c) = 1/2 (1/2*M*R²)*ωc² (2)
As both rotational kinetic energies must be equal each other, we can equate (1) and (2), as follows:
1/2 (2/5 M*R²)*ωs² = 1/2 (1/2*M*R²)*ωc²
Simplifying common terms, and solving for ωc, we have:
ωc = 2*ωs /√5
