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Ksju [112]
3 years ago
5

Determine how many times per second it would move back and forth across a 6.0-m-long room on the average, assuming it made very

few collisions with other molecules. Express your answer using two significant figures.
Physics
1 answer:
timofeeve [1]3 years ago
4 0

Answer:

The right solution is "24.39 per sec".

Explanation:

According to the question,

⇒ v=\frac{502.1}{\sqrt{3} }

      =289.9 \ m/s

The time will be:

⇒ t=\frac{d}{v}

      =\frac{2\times 6}{289.9}

      =\frac{12}{289.9}

      =0.041 \ sec

hence,

⇒ N=\frac{1}{t}

        =\frac{1}{0.041}

        =24.39 \ per \ sec

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