Question

Determine how many times per second it would move back and forth across a 6.0-m-long room on the average, assuming it made very few collisions with other molecules. Express your answer using two significant figures.

Answer 1

Answer:

The right solution is "24.39 per sec".

Explanation:

According to the question,

⇒ $v=\frac{502.1}{\sqrt{3} }$

      $=289.9 \ m/s$

The time will be:

⇒ $t=\frac{d}{v}$

      $=\frac{2\times 6}{289.9}$

      $=\frac{12}{289.9}$

      $=0.041 \ sec$

hence,

⇒ $N=\frac{1}{t}$

        $=\frac{1}{0.041}$

        $=24.39 \ per \ sec$