Answer:
kftisgkstisirstizurzursrus
Incomplete question as number of moles and length is missing.So I have assumed 3 moles and length of 0.300 m.So the complete question is here:
Three moles of an ideal gas are in a rigid cubical box with sides of length 0.300 m.What is the force that the gas exerts on each of the six sides of the box when the gas temperature is 20.0∘C?
Answer:
The Force act on each side is 2.43×10⁴N
Explanation:
Given data
n=3 mol
L=0.3 m
Temperature=20.0°C=293 K
To find
Force F
Solution
To get force act on each side it would employ by
F=P.A
Where P is pressure
A is Area
First we need to find pressure by applying ideal gas law
So

So The Force is given as:

The Force act on each side is 2.43×10⁴N
Answer:
the current value is 
Explanation:
The computation of the value of the current is given below:

Hence, the current value is 
Here is your answer
C. towards the floor
REASON:
Using Fleming's Left hand rule we can determine the direction of force applied on a moving charged particle placed in a magnetic field.
The direction of current will be just opposite to the direction of electron(negative charge) because current moves from positive to negative terminal whereas electron moves from negative to positive terminal.
So, direction of current- North to South
Now applying Fleming's Left hand rule we get the direction of force in downward direction, i.e. towards the floor.
HOPE IT IS USEFUL
Answer:
B
Explanation:
Remark
If, when it reaches its maximum height where the PE is the greatest, that the maximum energy is when the ball is first kicked. That would mean its starting energy is 10 Joules.
Formula
KE = 1/2 m v^2
Givens
KE = 10 J
m = 0.2 kg
v = ?
Solution
10 = 1/2 * 0.2 * v^2
10 * 2 = 0.2 * v^2
20 = 0.2 * v^2
20/0.2 = v^2
100 = v^2
v = 10 m/s