20. Entry to the fair is $10, and then you can
1 answer:
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Answer:
a) 0.4
b) 0.133
c)
Step-by-step explanation:
We are given the following information in the question:
The load is said to be uniformly distributed over that part of the beam between 90 and 105 pounds per linear foot.
a = 90 and b = 105
Thus, the probability distribution function is given by
a) P( beam load exceeds 99 pounds per linear foot)
P( x > 99)
b) P( beam load less than 92 pounds per linear foot)
P( x < 92)
c) We have to find L such that
The beam load should be greater than or equal to 99 such that the probability that the beam load exceeds L is 0.4.