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Ilia_Sergeevich [38]
3 years ago
8

Solve for x by factoring​

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0

Answer:

x = 5

Step-by-step explanation:

The area of the rectangle can be found by multiplying length x width:

Total Area = 55:

Length = x + 6

Width = x

Set the equation:

(x)(x + 6) = 55

First, distribute x to all terms within the parenthesis:

(x)(x + 6) = x² + 6x = 55

Next, set the equation equal to 0. Subtract 55 from both sides of the equation:

x² + 6x (-55) = 55 (-55)

x² + 6x - 55 = 0

Then, solve for x. Find factors of x² and -55 that, when combined, will result in 6x:

x² + 6x - 55 = 0

x              11

x            -5

(x + 11)(x - 5) = 0

Then, solve each individual parenthesis:

(x + 11) = 0

x + 11 (-11) = 0 (-11)

x = -11

(x - 5) = 0

x - 5 (+5) = 0 (+5)

x = 5

Note, however, that a side cannot have a negative measurement. Therefore, x = 5 is your only answer.

~

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nata0808 [166]

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Step-by-step explanation:

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Sliva [168]

Answer:

The graph of g(x) is wider.

Step-by-step explanation:

Parent function:

f(x)=x^2

New function:

g(x)=\left(\dfrac{1}{2}x\right)^2=\dfrac{1}{4}x^2

<u>Transformations</u>:

For a > 0

f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}

f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}

\begin{aligned} y =a\:f(x) \implies & f(x) \: \textsf{stretched/compressed vertically by a factor of}\:a\\ & \textsf{If }a > 1 \textsf{ it is stretched by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is compressed by a factor of}\: a\\\end{aligned}

\begin{aligned} y=f(ax) \implies & f(x) \: \textsf{stretched/compressed horizontally by a factor of} \: a\\& \textsf{If }a > 1 \textsf{ it is compressed by a factor of}\: a\\  & \textsf{If }0 < a < 1 \textsf{ it is stretched by a factor of}\: a\\\end{aligned}

If the parent function is <u>shifted ¹/₄ unit up</u>:

\implies g(x)=x^2+\dfrac{1}{4}

If the parent function is <u>shifted ¹/₄ unit down</u>:

\implies g(x)=x^2-\dfrac{1}{4}

If the parent function is <u>compressed vertically</u> by a factor of ¹/₄:

\implies g(x)=\dfrac{1}{4}x^2

If the parent function is <u>stretched horizontally</u> by a factor of ¹/₂:

\implies g(x)=\left(\dfrac{1}{2}x\right)^2

Therefore, a vertical compression and a horizontal stretch mean that the graph of g(x) is wider.

4 0
2 years ago
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