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Evgen [1.6K]
3 years ago
12

Y-4=3(x-1) identify the slope

Mathematics
1 answer:
Fantom [35]3 years ago
7 0

Answer: m = 3

Step-by-step explanation: convert to standard form 3x - y = -7

                                              slope using standard form

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the graph of y=e^tanx-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point? I g
Svetlanka [38]
Y = e^tanx   -   2

To find at which point it crosses x axis we state that y= 0

e^tanx   - 2 = 0 
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061

to find slope at that point first we need to find first derivative of funtion y.

y' = (e^tanx)*1/cos^2(x)

now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
3 0
2 years ago
Use the method of completing the square to transform the quadratic equation into the equation form (x + p)2 = q. 3 + x - 3x2 = 9
Triss [41]
To <span>transform the quadratic equation into the equation form (x + p)2 = q we shall proceed as follows:
3+x-3x^2=9
putting like terms together we have:
-3x^2+x=6
dividing through by -3 we get:
x^2-x/3=-2
but
c=(b/2a)^2
c=(-1/6)^2=1/36
thus the expression will be:
x^2-x/3+1/36=-2+1/36
1/36(6x-1)</span>²=-71/36

the answer is:
1/36(6x-1)²=-71/36
7 0
3 years ago
The area of the rectangle as a single expression
Ne4ueva [31]

Answer: A=15x^2+6x-48

Step-by-step explanation:

The area of a rectangle can be calculated with this formula:

A=l*w

Where "l" is the length and "w" is the width.

You can identify from the figure that the length and the width of this rectangle are:

length=3(x+2)\\width=5x-8

Then, you need to substitute this lenght and this width into A=l*w:

A=3(x+2)(5x-8)

Now, apply Distributive property:

A=(3x+6)(5x-8)\\\\A=15x^2-24x+30x-48

Finally, you need to add the like terms. Then, you get:

A=15x^2+6x-48

5 0
3 years ago
Find m∠A.<br> A. 32<br> B. 26<br> C. 27<br> D. 30
krok68 [10]
<h3>Answer: B. 26</h3>

============================================

Use law of cosines to find angle A

a^2 = b^2 + c^2 - 2*b*c*cos(A)

9^2 = 6^2 + 14^2 - 2*6*14*cos(A)

81 = 36 + 196 - 168*cos(A)

81 = 232 - 168*cos(A)

81 - 232  = -168*cos(A)

-151  = -168*cos(A)

-168*cos(A) = -151

cos(A) = (-151)/(-168)

cos(A) = 0.8988095

A = arccos(0.8988095)

A = 25.9979801

A = 26 degrees approximately

3 0
3 years ago
Question 21 (1 point) This table shows the input and output values for a linear function f(x). What is the positive difference o
Eva8 [605]

Answer:

2

Step-by-step explanation:

x     f(x)      

−3    −1.5

−2    −1

−1     −0.5

0     0

1      0.5

2     1

3     1.5

This table shows the input and output values for a linear function f(x).

Now, two inputs which are four values apart are say -3 and 1 and the corresponding outputs are - 1.5 and 0.5.

Therefore, the positive difference of outputs is [0.5 - (- 1.5)] = 2 (Answer)

8 0
2 years ago
Read 2 more answers
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