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Mumz [18]
3 years ago
15

Twelve is added to the product of a number and 5. The result is -3. Find the number

Mathematics
2 answers:
3241004551 [841]3 years ago
5 0
I would say that the number is -20 because 12+5=17, but your answer is -3 so basically just think of a number higher than 17 and that would make your answer a negative. Your answer is 20
TiliK225 [7]3 years ago
4 0
5 + -8 = -3.

So the answer would be -8.
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X+8=-2<br><br> O A. x= 10<br> OB. x=-6<br> O C. x=6<br> OD. x= -10
MaRussiya [10]

Answer: option D

Step-by-step explanation:

X+8=-2

    x= -2-8 (you should make x the subject so you switch the +8 to the other

    x= -10                                                                   side which becomes -8)    

so you get -10 because, if both the numbers have the minus sign then you should add the two values which will be a negative answer. So your answer is option D  

5 0
2 years ago
Read 2 more answers
How would you write x+3y=3 in y=mx+b format
Triss [41]
X+3y=3
First add subtract the x
3y=-x+3
Then divide 3
Y=-1/3x+1
8 0
3 years ago
Read 2 more answers
Which of the following are true statements.
Mariulka [41]

Answer:

Second statement is true.

The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

Step-by-step explanation:

for first part of statement

The lengths 7, 40 and 41 can not be sides of a right triangle.

If the square of long side is equal to the sum of square of other two sides

then the given length can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

c^{2} =a^{2} +b^{2}----------(1)

Let c=41 and a = 7 and b=40

Put all the value in equation 1.

41^{2} =7^{2} +40^{2}

1681=49+1600

1681=1649

Therefore, the square of long side is not equal to the sum of square of other two sides, So given lengths 7, 40 and 41 can not be sides of a right triangle.

for second part of statement.

The lengths 12, 16, and 20 can be sides of a right triangle.

Check the given length by Pythagoras Theorem.

Let c=20 and a = 12 and b=16

20^{2} =12^{2} +16^{2}

400=144+256

400=400

Therefore, the square of long side is equal to the sum of square of other two sides, So given the lengths 12, 16, and 20 can be sides of a right triangle.

Therefore, The lengths 7, 40 and 41 can not be sides of a right triangle. The lengths 12, 16, and 20 can be sides of a right triangle.

8 0
3 years ago
To avoid modeling the physical characteristics of wheel encoders such the square wave outputs, it is desirable to generate encod
grandymaker [24]

Answer:

The probability distribution is  Normal continuous

Step-by-step explanation:

The basic idea is that velocity values have different noise level and an important thing regarding continuous probability distributions is that the probability of the random variable is equal to a specific outcome is 0

In other words, is practically impossible that one value of velocity could be the same as others.

5 0
3 years ago
What are the x and y values....?<br><br> -1x + 2y = 18 <br><br> Haylp me pls!
Nesterboy [21]
Use the zeroes to figure this out... x=-18, y=9
7 0
4 years ago
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