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ololo11 [35]
3 years ago
9

True or False. A compact disc (CD) stores music in a coded pattern of tiny pits 10−7m deep. The pits are arranged in a track tha

t spirals outward toward the rim of the disc; the inner and outer radii of this spiral are 25.0 mm and 58.0 mm, respectively. As the disc spins inside a CD player, the track is scanned at a constant linear speed of 1.25 m/s.
Computers and Technology
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

True.

Explanation:

Yes it is true. A CD works on exactly the same pattern defined above.

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DSSS uses a chipping code to encode redundant data into the modulated signal. Which two of the following are examples of chippin
Schach [20]

Answer:

Option A and Option D

Explanation:

5 0
4 years ago
Which is a example of fixed expense <br><br> -food<br> -clothing<br> -entertainment<br> -rent
Artemon [7]
Salutations!

<span>Which is an example of fixed expense?

Rent is an example of fixed expense, It doesn't matter whether you sell a widget or produce thousand of them, you must still pay the rent in any </span><span>circumstances.
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Hope I helped.
6 0
4 years ago
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Suppose the daytime processing load consists of 65% CPU activity and 35% disk activity. Your customers are complaining that the
bekas [8.4K]

Answer:

The answer to this question can be described as follows:

Explanation:

Given data:

Performance of the CPU:  

The Fastest Factor Fraction of Work:

f_1=65 \% \\\\=\frac{65}{100} \\\\ =0.65

Current Feature Speedup:

K_1= 1.5

CPU upgrade=6000

Disk activity:

The quickest part is the proportion of the work performed:

Current Feature Speedup:

k_2=3

Disk upgrade=8000

System speedup formula:

s=\frac{1}{(1-f)+(\frac{f}{k})}

Finding the CPU activity and disk activity by above formula:

CPU activity:

S_{CPU}=\frac{1}{(1-f_1)+(\frac{f_1}{k_1})} \\\\=\frac{1}{(1-0.65)+(\frac{0.65}{1.5})} \\\\=1.276 \%  ...\rightarrow (1) \\

Disk activity:

S_{DISK} = (\frac{1}{(1-f_2)+\frac{f_2}{k_2}}) \\\\ S_{DISK} = (\frac{1}{(1-0.35)+\frac{0.35}{3}}) \\\\ = -0.5\% .... \rightarrow (2)

CPU:

Formula for CPU upgrade:

= \frac{CPU \ upgrade}{S_{CPU}}\\\\= \frac{\$ 6,000}{1.276}\\\\= 4702.19....(3)

DISK:

Formula for DISK upgrade:

=\frac{Disk upgrade} {S_{DISK}}\\\\= \frac{\$ 8000}{-0.5 \% }\\\\= - 16000....(4)

equation (3) and (4),

Thus, for the least money the CPU alternative is the best performance upgrade.

b)

From (3) and (4) result,

The disc choice is therefore the best choice for a quicker system if you ever don't care about the cost.

c)

The break-event point for the upgrades:

=4702.19 x-0.5

= -2351.095

From (2) and (3))

Therefore, when you pay the sum for disc upgrades, all is equal $ -2351.095

4 0
3 years ago
What is a sloper
Andreas93 [3]

Answer:

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Explanation:

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7 0
3 years ago
The purpose of a business report is to _____.
mars1129 [50]
Im pretty sure the answer is 2.
4 0
3 years ago
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