Answer:
80π
Step-by-step explanation:
Circle O with radius IO:
large radius = IO = 12 = R
Circle O with diameter JK
IJ = JK = KL = 2 × IO = 24
IJ = JK = KL = 24/3 = 8
small radius = 8/2 = 4 = r
The shaded area is a semicircle of radius 12 minus a semicircle of radius 4 plus two semicircles of radius 4.
That is the same as
1 semicircle of radius 12 plus 1 semicircle of radius 4
A = πR²/2 + πr²/2
A = π(12² + 4²)/2
A = 160π/2
A = 80π
Answer:
where?
Step-by-step explanation:
.............
The domain of the relationship is [-2,6]
//You need to factorise the two quadratics and divide where possible
x^2 + 3x + 2 = (x+2)(x+1)
x^2 - 4 = (x+2)(x-2)
y = (x+2)(x+1)/(x+2)(x-2)
y = (x+1)/(x-2)
It's $0.44 cents my good friend......