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Triss [41]
3 years ago
13

Find the perimeter of the quarter-circle. Give your answer to the nearest whole number.

Mathematics
2 answers:
Nikitich [7]3 years ago
8 0
Yes correct yay ! :)
Bezzdna [24]3 years ago
6 0

Answer:

The perimeter of the quarter-circle is 200 cm.

Step-by-step explanation:

Given that the angle of quarter-circle is 90°. So using Length of Arc formula, you are able to find the length of curve :

arc =  \frac{θ}{360}  \times 2 \: \pi \: r

Let r be radius = 56 cm,

Let θ = 90°

arc =  \frac{90}{360}  \times 2 \times\pi \times 56

=  \frac{1}{4}  \times 2 \times \pi \times 56

=  \frac{1}{2}  \times \pi \times 56

= 28\pi \: cm

We have already found the arc. Next we have to add up together to find the perimeter :

p = 56 + 56 + 28\pi

p = 112 + 28\pi

p = 200 \: cm \: (3s.f)

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Given: f(x) = 2x + 5, match the inputs with their outputs.
bekas [8.4K]
Yeah the answer is number 5
3 0
3 years ago
Tony is using these numbers to make a new number: 12, 1, 4, 7.
natulia [17]

Answer:

420

Step-by-step explanation:

(12 x 7) x (1+4)

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=420

7 0
3 years ago
An arborist examined trees in an orchard to see if they were infected with a virus. Out of 90 trees, 40% had the virus. How many
Harman [31]

Answer:

36 trees were infected with the virus.

Step-by-step explanation:

Given:

Total number of trees =  90

Percentage of tree that had virus  40%

To find:

Number of tress that were infected by virus = ?

Solution:

Let the number trees that was affected by the virus be X.

then

X = 40% of 90

X = \frac{40}{100} \times 90

X = 0.4 \times 90

X= 36

6 0
3 years ago
The number of nails of a given length is normally distributed with a mean length of 5 in and a standard deviation of 0.03 find t
umka2103 [35]

Answer:

19 nails

Step-by-step explanation:

Let's first determine the z-score by using the formula:

z=\frac{x-\mu}{\sigma}

Where x=5.03, μ=5, σ=0.03 and so:

z=\frac{5.03-5}{0.03}=1


We can now use a z-score table to determine that 1.00 is synonymous with 0.8413 meaning 84.13%.  This means that 84.13% of the nails are less than or equal to 5.03 inches long.  Therefore, since we know 100% = 1 in decimals we can determine that the length greater than 5.03 inches is 1-0.8413=0.1587.  This means that 15.87% of the 120 nails are greater than 5.03 inches long.

Finally, we can determine how many nails are greater than 5.03 by determining what is 15.87% of 120 which is:

120 \times 0.1587 \approx 19

And so 19 out of the 120 nails are greater than 5.03 inches long.

5 0
3 years ago
Which of these match plz don’t say random ones more then one answer possibly
natali 33 [55]
A and E
Just rearrange where the -5 is
3 0
3 years ago
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