Answer:
22572J
Explanation:
a) The following values have been given:
Mass of water = 180.0g
Initial temperature = 10°C
Final temperature = 40°C
molar heat capacity for water = 75.3J/Kmol
To calculate the specific heat capacity of water (c), we divide the molar heat capacity by molar mass of water (18g/mol)
That is; 75.3/18
= 4.183 Jg/K
b) The enthalpy change denoted by ∆H is the value we are trying to find.
c) To find enthalpy change (∆H), we use the formula:
∆H = m × c × ∆T
Where; m= mass
c= specific heat capacity
∆T= change in temperature =
(final temp - initial temp)
∆H = m × c × ∆T
∆H = 180 × 4.18 × (40-10)
∆H = 180 × 4.18 × 30
∆H = 22572J
