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Hunter-Best [27]
3 years ago
10

*

Chemistry
1 answer:
Strike441 [17]3 years ago
5 0
D. The kilogram is a unit of mass.
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The stability of an isotope is based on its
lidiya [134]

Answer:

It is believed that the stability of an isotope is based on the ratio of neutrons to protons.

+if this helped you, please consider marking it the Brainliest in order to help me unlock the next achievement.

4 0
3 years ago
Which one is used in magnets often nickle or lead?
astra-53 [7]
In magnet I believe nickle is used most often
7 0
3 years ago
At STP, which gas sample has a volume of 11.2 liters?
Natasha2012 [34]

Answer:

0.500 moles of CO2 has a volume of 11.2 L at STP (option B)

Explanation:

Step 1: Data given

Volume of a gas at STP = 11.2 L

STP: Pressure = 1 atm  and temperature = 273 K

Step 2: Calculate volume

p*V= n*R*T

V = (n*R*T)/p

⇒with V = the volume of the gas = TO BE DETERMINED

⇒with n = the number of moles of the gas

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 273 K

⇒with p = the pressure of the gas = 1 atm

A ) 0.250 mole of NH3

V = (0.250 * 0.08206 * 273) / 1

V = 5.6 L

B ) 0.500 mole of CO2

V = (0.500 * 0.08206 * 273) / 1

V = 11.2 L

C ) 0.750 mole of NH3

V = (0.750 * 0.08206 * 273) / 1

V = 16.8 L

D) 1.00 mole of CO2

V = (1.00 * 0.08206* 273) / 1

V = 22.4 L

0.500 moles of CO2 has a volume of 11.2 L at STP (option B)

3 0
4 years ago
What is the importance of the central vacuole in plant cells
tamaranim1 [39]

Central Vacuole in plant cells:

- holds materials and wastes.

- provide structure and support for the growing plant.


Hope this helped and plz mark as brainliest!

7 0
3 years ago
Read 2 more answers
Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.
Sindrei [870]

The molar solubility is 7.4×10^{-3} M and the solubility is  7.4×10^{-3} g/L .

Calculation ,

The dissociation of silver bromide is given as ,

AgBr → Ag ^{+} + Br^{-}

S  

 -          S        S        

Ksp =  [Ag ^{+} ] [ Br^{-} ]  =  [S] [ S ] = S^{2}

S = √ Ksp = √ 5. 5×10^{-5} = 7.4×10^{-3}

The solubility =7.4×10^{-3} g/L

The molar solubility is the solubility of one mole of the substance.

Since ,  one mole of AgBr is dissociates and form one mole of each  Ag ^{+} and Br^{-} ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4×10^{-3} mol/L = 7.4×10^{-3} M

To learn more about molar solubility ,

brainly.com/question/16243859

#SPJ4

7 0
1 year ago
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