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3 years ago

Please answer fast do in 5 mins Body System used for support, movement, structure and makes red blood cells

Chemistry

1 answer:

pochemuha3 years ago

7 0

Explanation:

The Skeletal System (A).

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"A solution with a total volume of 850.0 mL contains 43.5 g Mg(NO3)2. If you remove 25.0 mL of this solution and then dilute thi

ycow [4]

Answer: C = 0.014M

Explanation:

From n= m/M= CV

m =43.5 M= 148, V=850ml

43.5/148= C× 0.85

C= 0.35M

Applying dilution formula

C1V1=C2V2

C1= 0.35, V1= 25ml, C2=?, V2= 600ml

0.35× 25 = C2× 600

C2= 0.014M

7 0

4 years ago

200 + O2 → 2CO2

Ugo [173]

ANSWER 10 MOLES OF CARBON DIOXIDE

2C0 + O2 → 2CO2

2 moles of carbon monoxide forming 2 moles of carbon dioxide

10 moles of carbon monoxide will form 10 moles of carbon dioxide

4 0

3 years ago

0.0400 M solution of HClO2, pH = 1.80 solve for Ka

umka2103 [35]

Ka for weak acids is ---> Ka= (X)²/ (initial- X)

initial= 0.0400 M

to find X, you can find the H concentration using pH

[H+]= 10^-pH
[H+]= 10^-1.80= 0.016 which is X

ka = (0.016)²/ (0.0400 - 0.016) = 0.011

6 0

4 years ago

A 575.4575.4 mL sample of carbon dioxide was heated to 377377 K. If the volume of the carbon dioxide sample at 377377 K is 824.7

Margaret [11]

Answer:

263 K

Explanation:

Assuming ideal behaviour and constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:

T₁V₂=T₂V₁

In this case:

T₁ = ?

V₂ = 824.7 mL

T₂ = 377 K

V₁ = 575.45 mL

We input the data:

T₁ * 824.7 mL = 377 K * 575.45 mL

And solve for T₁:

T₁ = 263 K

3 0

3 years ago

An atom of 105In has a mass of 104.914558 amu. Calculate the binding energy in MeV per NUCLEON. Enter your answer with 3 signifi

joja [24]

Answer:

8.46

Explanation:

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Also, atomic number of I = 549

Thus, the number of protons = 49

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

105 = 49 + Number of neutrons

Number of neutrons = 56

Mass of neutron = 1.008665 amu

Mass of proton = 1.007825 amu

Calculated mass = Number of protons*Mass of proton + Number of neutrons*Mass of neutron

Thus,

Calculated mass = (49*1.007825 + 56*1.008665) amu = 105.868665 amu

Mass defect = Δm = |105.868665 - 104.914558| amu = 0.954107 amu

The conversion of amu to MeV is shown below as:-

1 amu = 931.5 MeV

So, Energy = 0.954107*931.5 MeV/atom = 888.750671 MeV/atom

Also, 1 atom has 105 nucleons (Protons+neutrons)

So, Energy = 888.750671 MeV/105nucleons = 8.46 MeV/nucleon

Answer:- 8.46

8 0

3 years ago