Please answer fast do in 5 mins Body System used for support, movement, structure and makes red blood cells

Which two columns have identical data? What do these two columns suggest about the identity of elements?

Gnesinka [82]

Answer:

Explanation:

Atomic number and number of protons have identical data. These two columns suggest that the atomic number is the same as the number of protons in an atom.

3 0

3 years ago

Convert 296 degrees Celsius to Kelvin. A. 23 K B. 552 K C. 569 K D. 550 K

katovenus [111]

Answer:

option c) 552 K is correct

Explanation:

we know that

0° C +273= 273 K

so

296° C+273=569 K

7 0

2 years ago

Read 2 more answers

Sam prepares a solution of sodium chloride with a concentration of 8 g/dm³. If he only used 2g of sodium chloride, what volume o

adoni [48]

The volume of water he dissolved the solute is 250 cubic centimeter.

Explanation:

Concentration = mass of solute in g / volume in dm^3

The concentration of a solution is defined as the ratio of mass of solute in grams to the volume of water in dm^3.

If concentration of a solution = 8 g/dm^3.

mass of solute =2 g.

Volume of a water = 2 / 8 = 0.25 dm^3. (or) 250 cubic centimeter.

4 0

3 years ago

What is the balanced net precipitation reaction for BaCl2 and KOH?

Dmitrij [34]

BaCl2 reacts with KOH forming KCl which is a salt and Ba(OH)2 which is the precipitate.
The initial UNBALANCED equation expressing this reaction would be:
BaCl2 + KOH .............> KCl + Ba(OH)2
Now, we need to balance this equation:
we have two moles of Cl as reactants and one mole only as product. Therefore, we will multiply the KCl in the product by 2 and the KOH in the reactants by 2.
This will balance the equation as follows:
BaCl2 + 2KOH ......> 2KCl + Ba(OH)2

Noticing this equation, we will find that:
The precipitate was formed due to the combination of the Ba2+ ion with 2 OH- ions as follows:
Ba2+ + OH- ............> Ba(OH)2

7 0

4 years ago

How many liters are there in 144g of H₂O (g)? What is the mass of 200L at STP of H₂O₂ (g)?

Lisa [10]

Answer:

1. 179.2 L

2. 303.62 g

Explanation:

1. Determination of volume of H₂O (g).

We'll begin by calculating the number of mole in 144 g of H₂O. This is illustrated below:

Mass of H₂O = 144 g

Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mole of H₂O =?

Mole = mass /Molar mass

Mole of H₂O = 144/18

Mole of H₂O = 8 moles

Finally, we shall determine volume of H₂O (g) as follow:

1 mole of any gas occupy 22.4L at stp.

Therefore, 8 moles of H₂O (g) will occupy =

8 × 22.4 = 179.2 L

Thus, 144 g of H₂O (g) occupies 179.2 L

2. Determination of the mass of H₂O₂ (g).

We'll begin by calculating the number of mole of H₂O₂ (g) that occupied 200 L at STP. this can be obtained as follow:

1 mole of any gas occupy 22.4 L at stp.

Therefore, Xmol of H₂O₂ (g) will occupy 200 L at STP i.e

Xmol of H₂O₂ (g) = 200/22.4

Xmol of H₂O₂ (g) = 8.93 moles

Thus, 8.93 moles of H₂O₂ (g) occupied 200 L at STP.

Finally, we shall determine the mass of H₂O₂ (g) as follow:

Mole of H₂O₂ (g) = 8.93 moles

Molar mass of H₂O₂ = (2×1) + (2×16) = 2 + 32 = 34 g/mol

Mass of H₂O₂ =?

Mole = mass /Molar mass

8.93 = mass of H₂O₂ /34

Cross multiply

Mass of H₂O₂ = 8.93 × 34

Mass of H₂O₂ = 303.62 g

5 0

3 years ago