Part 1:
Fixed Cost, f = $20
number of balls = n
Cost of each ball, c = 4.32
Price of each ball, p = 8.32
Equation for total cost:
Total Cost of balls will come by adding the cost of all balls and the fixed cost
Total Cost = number of balls made × Cost of each ball + fixed cost
<em>C = 4.32n + 20</em>
Equation for revenue:
Revenue = Number of balls made × price of each ball
<em>R = 8.32n </em>
Part 2:
Use the graphing method to determine how many balls must be sold to break even
Breakeven means Revenue = total Cost
This happens at a point (5,41.6) where n = 5 is the number of balls sold
and C = 41.6 is the total cost
When 5 balls are sold there will be breakeven
R = 4n - 20
C = 4.32n + 20
Red line represent Cost
Black line represent Revenue
Answer:
y^35
Step-by-step explanation:
<span>Simplifying
3a2 + -2a + -1 = 0
Reorder the terms:
-1 + -2a + 3a2 = 0
Solving
-1 + -2a + 3a2 = 0
Solving for variable 'a'.
Factor a trinomial.
(-1 + -3a)(1 + -1a) = 0
Subproblem 1Set the factor '(-1 + -3a)' equal to zero and attempt to solve:
Simplifying
-1 + -3a = 0
Solving
-1 + -3a = 0
Move all terms containing a to the left, all other terms to the right.
Add '1' to each side of the equation.
-1 + 1 + -3a = 0 + 1
Combine like terms: -1 + 1 = 0
0 + -3a = 0 + 1
-3a = 0 + 1
Combine like terms: 0 + 1 = 1
-3a = 1
Divide each side by '-3'.
a = -0.3333333333
Simplifying
a = -0.3333333333
Subproblem 2Set the factor '(1 + -1a)' equal to zero and attempt to solve:
Simplifying
1 + -1a = 0
Solving
1 + -1a = 0
Move all terms containing a to the left, all other terms to the right.
Add '-1' to each side of the equation.
1 + -1 + -1a = 0 + -1
Combine like terms: 1 + -1 = 0
0 + -1a = 0 + -1
-1a = 0 + -1
Combine like terms: 0 + -1 = -1
-1a = -1
Divide each side by '-1'.
a = 1
Simplifying
a = 1Solutiona = {-0.3333333333, 1}</span>
Answer:
They are supplementary
Step-by-step explanation:
Since AB and DC are parallel, then the alternate interior angles are congruent because there is transversal cutting the parallel lines (BC). So m<B is supplementary to m<C
