So:
(x-4)(x+2) / (x-4)(x+4)
We cancel out the x - 4:
(x+2)/(x+4)
Restrictions: x ≠ 4, x ≠ -4
The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
Answer:
B)
Step-by-step explanation:
4y = 3x + 5 has a slope of 3/4
4y = 3x - 1 has a slope of 3/4
parallel lines have equal slopes
Answer:
f = -3/4
Step-by-step explanation:
13f + 6 -f = -3
Combine like terms
12f +6 = -3
Subtract 6 from each side
12f+6-6 = -3-6
12f = -9
Divide each side by 12
12f/12 = -9/12
f = -3/4
4 is a coefficient and X and Y are variables so the -110 is the constant so there for the answer is D
