Answer: a. 0.1031; fail to reject the null hypothesis
Step-by-step explanation:
Given: Significance level : 
The test statistic in a two-tailed test is z = -1.63.
The P-value for two-tailed test : 
[By p-value table]
Since, 0.1031 > 0.05
i.e. p-value > 
So, we fail to reject the null hypothesis. [When p< then we reject null hypothesis ]
So, the correct option is a. 0.1031; fail to reject the null hypothesis.
Alrighty, so 280.05 rounded to the nearest integer is 280. 280.05 rounded to tenths is 280.1. add those two together and you get 560.1.
Step-by-step explanation:
÷6
First, simplify the 6 to an improper fraction, which is:
Next rewrite the equation using the improper fraction:
÷
Now, in order to divide the fraction, we will need to flip the second fraction over, and then multiply the two fractions together. A great way to remember this is the phrase <em>Copy Dot Flip - </em>Copy the first fraction, put a dot for multiplication, and flip the second fraction.
·
Finally, multiply together and simplify/reduce if needed:
<u>The final answer is </u>
<u> and no simplification or reduction is needed</u>
The value of TV is 11.
<h3>What is equation?</h3>
An equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Given:
TU= 8, UV = 3x and TV = x+10
TV= TU + UV
x +10= 8+ 3x
-2x = -2
x= 1
Hence, TV = 1+10= 11.
Learn more about equation here:
brainly.com/question/10413253
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Answer:
The data in country B are more symmetric than the data in country A.
Step-by-step explanation:
The following information is missing:
<em>The box plots show the average wind speeds, in miles per hour, for various cities in two different countries. Average Wind Speeds of Cities in Country A 2 box plots. The number line goes from 1 to 11. For the average wind speeds of cities in country A, the whiskers range from 1 to 9.5, and the box ranges from 3 to 7. A line divides the box at 4. For the average wind speeds of cities in country B, the whiskers range from 1.2 to 11, and the box ranges from 4 to 9. A line divides the box at 6. Average Wind Speeds of Cities in Country B</em>
Country A
Country B
We can see that the difference between quartile 1 and minimum, median and quartile 1, quartile 3 and median, and maximum and quartile 3 is more homogeneous in Country B than Country A, then Country B is more symmetric.
