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mr_godi [17]
3 years ago
9

The input of days results in the output of total collected books. On day 1, 8 books were collected. Both inputs for days 2 and 3

have the same output of 13, meaning that no books were collected for day 3. After 5 days, 21 books were collected. The most books were collected on day 5.
Mathematics
1 answer:
Paul [167]3 years ago
5 0
Among 34- to 39-year-olds, 32% say they have driven while under the influence of alcohol. Suppose that seven 34- to 39-year-olds are selected at random.

a)What is the probability that all seven have driven while under the influence of alcohol?

(b) What is the probability that at least one has not driven while under the influence of alcohol?

(c) What is the probability that none of the seven has driven while under the influence of alcohol?
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Can somebody help me seriously
Semmy [17]

Answer: b

Step-by-step explanation:

I don't know but i am right

7 0
2 years ago
The function t(x) = 3x + 5 determines how many cans of corn kernels a food truck needs to stock, where x is the number of shifts
Inessa [10]

Answer: 31


Step-by-step explanation:

Given: The function t(x) = 3x + 5 determines how many cans of corn kernels a food truck needs to stock, where x is the number of shifts the crew is going to work in the truck.

At x=3

t(3)=3(3)+5=14

The crew uses c(t(x)) to find the amount of money to spend on corn. The function c(x) = 2x + 3

When the crew is going to work 3 shifts,the amount of money must be spent

=c(t(x))=c(14)=2(14)+3=28+3=31

The amount of money must be spent when the crew is going to work 3 shifts=31

6 0
3 years ago
Read 2 more answers
Elley is mixing blue and yellow food coloring to make green food coloring for her bakery. The relationship between the amounts o
grin007 [14]
A. Kelley uses 2 parts blue for every 3 parts yellow
7 0
3 years ago
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Find the dimensions of the rectangle with largest area that can be inscribed in an equilateral triangle with sides of 1 unit, if
prohojiy [21]
<span>Maximum area = sqrt(3)/8 Let's first express the width of the triangle as a function of it's height. If you draw an equilateral triangle, then a rectangle using one of the triangles edges as the base, you'll see that there's 4 regions created. They are the rectangle, a smaller equilateral triangle above the rectangle, and 2 right triangles with one leg being the height of the rectangle and the other 2 angles being 30 and 60 degrees. Let's call the short leg of that triangle b. And that makes the width of the rectangle equal to 1 minus twice b. So we have w = 1 - 2b b = h/sqrt(3) So w = 1 - 2*h/sqrt(3) The area of the rectangle is A = hw A = h(1 - 2*h/sqrt(3)) A = h*1 - h*2*h/sqrt(3) A = h - 2h^2/sqrt(3) We now have a quadratic equation where A = -2/sqrt(3), b = 1, and c=0. We can solve the problem by using a bit of calculus and calculating the first derivative, then solving for 0. But since this is a simple quadratic, we could also take advantage that a parabola is symmetrical and that the maximum value will be the midpoint between it's roots. So let's use the quadratic formula and solve it that way. The 2 roots are 0, and 1.5/sqrt(3). The midpoint is (0 + 1.5/sqrt(3))/2 = 1.5/sqrt(3) / 2 = 0.75/sqrt(3) So the desired height is 0.75/sqrt(3). Now let's calculate the width: w = 1 - 2*h/sqrt(3) w = 1 - 2* 0.75/sqrt(3) /sqrt(3) w = 1 - 2* 0.75/3 w = 1 - 1.5/3 w = 1 - 0.5 w = 0.5 The area is A = hw A = 0.75/sqrt(3) * 0.5 A = 0.375/sqrt(3) Now as I said earlier, we could use the first derivative. Let's do that as well and see what happens. A = h - 2h^2/sqrt(3) A' = 1h^0 - 4h/sqrt(3) A' = 1 - 4h/sqrt(3) Now solve for 0. A' = 1 - 4h/sqrt(3) 0 = 1 - 4h/sqrt(3) 4h/sqrt(3) = 1 4h = sqrt(3) h = sqrt(3)/4 w = 1 - 2*(sqrt(3)/4)/sqrt(3) w = 1 - 2/4 w = 1 -1/2 w = 1/2 A = wh A = 1/2 * sqrt(3)/4 A = sqrt(3)/8 And the other method got us 0.375/sqrt(3). Are they the same? Let's see. 0.375/sqrt(3) Multiply top and bottom by sqrt(3) 0.375*sqrt(3)/3 Multiply top and bottom by 8 3*sqrt(3)/24 Divide top and bottom by 3 sqrt(3)/8 Yep, they're the same. And since sqrt(3)/8 looks so much nicer than 0.375/sqrt(3), let's use that as the answer.</span>
7 0
3 years ago
Read 2 more answers
Using pythagorean theorem find a, and b, where a is twice of b and the hypotonuse is 5√5
patriot [66]
Measure of Hypotaneous = 5√5

And it's already given that b = 2a

By using pythagoras theorem:

a²+ b² = (5√5)²

Let's substitute for b as 2a in above equation we'll get:

a² + (2a)² = (5√5)²

a² + 4a² = 125
5a² = 125
a² = 25
a = √25 = 5


Therefore,
a= 5
and
b = 2a = 2(5) = 10.


3 0
3 years ago
Read 2 more answers
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