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3 years ago

10

How do I solve this ?

1 answer:

xenn [34]3 years ago

8 0

To solve these problems, you must make the denominators of each fraction match, before adding.

2. The answer is 11/10 or 1 and 1/10.

To find this answer, multiply 1/5 by 2/2 to get 2/10. Then add 2/10 to 9/10 get 11/10 or 1 and 1/10 as your answer.

4. The answer is 23/18 or 1 and 5/18.

To find this answer, multiply 7/9 by 2/2 to get 14/18, and multiply 1/2 by 9/9 to get 9/18. Then add 14/18 and 9/18 to get 23/18 or 1 and 5/18 as your answer.

6. The answer is 7/12.

To find this answer, multiply 1/3 by 4/4 to get 4/12 and multiply 1/4 by 3/3 to get 3/12. Then add 4/12 and 3/12 to get 7/12 as your answer.

I hope this helps!

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How the position of the decimal point changes in a quotient as you divide by increasing powers 10

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The position of the decimal point changes in a quotient as you divide by increasing the powers 10.

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3 years ago

Pls help! <br> and a reason.

Rasek [7]

Answer:

$\angle BDA = 72^{\circ}$

$\angle DAB = 36^{\circ}$

$\angle BDC = 108^{\circ}$

$\angle BCD = 36^{\circ}$

$\angle DBC = 36^{\circ}$

Step-by-step explanation:

Given

$\angle ABD = 72^{\circ}$

Required

Determine the missing angles

Since AB = AD, then:

$\angle ABD = \angle BDA$ --- Base angles of an isosceles triangle

Hence:

$\angle ABD = \angle BDA = 72^{\circ}$

$\angle ABD + \angle BDA + \angle DAB = 180^{\circ}$ --- angles in a triangle

$72^{\circ} + 72^{\circ} + \angle DAB = 180^{\circ}$

$144^{\circ} + \angle DAB = 180^{\circ}$

Collect Like Terms

$\angle DAB = 180^{\circ} - 144^{\circ}$

$\angle DAB = 36^{\circ}$

$\angle BDA + \angle BDC = 180^{\circ}$ --- angle on a straight line

$72^{\circ} + \angle BDC = 180^{\circ}$

$\angle BDC = 180^{\circ} - 72^{\circ}$

$\angle BDC = 108^{\circ}$

Since ABC is isosceles, then:

$\angle DAB = \angle BCD = 36^{\circ}$ --- base angle of isosceles

$\angle BCD = 36^{\circ}$

Lastly:

$\angle BCD + \angle BDC + \angle DBC = 180^{\circ}$

$36^{\circ} + 108^{\circ} + \angle DBC = 180^{\circ}$

$\angle DBC = 180^{\circ} - 36^{\circ} - 108^{\circ}$

$\angle DBC = 36^{\circ}$

<em>See attachment</em>

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I hope this helps! If not I'm sorry.

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