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choli [55]
3 years ago
10

How do I solve this ?

Mathematics
1 answer:
xenn [34]3 years ago
8 0

To solve these problems, you must make the denominators of each fraction match, before adding.

2. The answer is 11/10 or 1 and 1/10.

To find this answer, multiply 1/5 by 2/2 to get 2/10. Then add 2/10 to 9/10 get 11/10 or 1 and 1/10 as your answer.

4. The answer is 23/18 or 1 and 5/18.

To find this answer, multiply 7/9 by 2/2 to get 14/18, and multiply 1/2 by 9/9 to get 9/18. Then add 14/18 and 9/18 to get 23/18 or 1 and 5/18 as your answer.

6. The answer is 7/12.

To find this answer, multiply 1/3 by 4/4 to get 4/12 and multiply 1/4 by 3/3 to get 3/12. Then add 4/12 and 3/12 to get 7/12 as your answer.

I hope this helps!

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Viktor [21]

Answer:

7,920 feet : 30 minutes

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Rename 3/4 and 9/10 using the least common denominator.
klio [65]

Answer:

15/20 and 18/20

Step-by-step explanation:

Least common denomintor of 3/4 and 9/10 = least common multiple of 4 and 10

multiples of 4: 4, 8, 12, 16, 20

multiples of 10: 10, 20

Least common denominator = 20

Rewrite fractions: 15/20 and 18/20

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Simplify the equation
Arturiano [62]

Answer:

\dfrac{16x^3-37x^2-16x+37}{x^2+2}

Step-by-step explanation:

There aren't any factors that cancel (except 3x). The best you can do is multiply it out.

\displaystyle\frac{\frac{3x^2-3}{x}}{\frac{3(x^2+2)}{16x^2-37x}}=\frac{3(x^2-1)}{x}\cdot\frac{16x^2-37x}{3(x^2+2)}\\\\=\frac{x(x^2-1)(16x-37)}{x(x^2+2)}=\frac{16x^3-37x^2-16x+37}{x^2+2}

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3 years ago
Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t
Pepsi [2]

Answer:

Step-by-step explanation:

Two lines are perpendicular if the first line has a slope of m and the second line has a slope of \frac{1}{-m}.

With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:

5x - 2y = -6

-2y = -5x - 6

y = \frac{5}{2}x + 3

We now know that m = \frac{5}{2} for the first line, which means that the slope of the second line is m = \frac{-2}{5}. With this, we have the following equation for our new line:

y = \frac{-2}{5}x + C

where C is the Y-intercept that we now need to determine with the coordinates given in the problem statement, (5, -4):

y = \frac{-2}{5}x + C

(-4) = \frac{-2}{5}(5) + C

-4 = -2 + C

C = -2

Finally, we can create our line:

y = \frac{-2}{5}x - 2

5y = -2x - 10

2x + 5y = -10

8 0
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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv
ch4aika [34]

Answer:

Part 1) The function of the First graph is f(x)=(x-3)(x+1)

Part 2) The function of the Second graph is f(x)=-2(x-1)(x+3)

Part 3) The function of the Third graph is f(x)=0.5(x-6)(x+2)

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

f(x)=a(x-c)(x-d)

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-3)(x+1)

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

-4=a(1-3)(1+1)

-4=a(-2)(2)

a=1

therefore

The function is equal to

f(x)=(x-3)(x+1)

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

f(x)=a(x-1)(x+3)

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

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8=a(-2)(2)

a=-2

therefore

The function is equal to

f(x)=-2(x-1)(x+3)

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

f(x)=a(x-6)(x+2)

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

-8=a(2-6)(2+2)

-8=a(-4)(4)

a=0.5

therefore

The function is equal to

f(x)=0.5(x-6)(x+2)

3 0
3 years ago
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