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2 years ago

What is the exact volume of the cone? (height is 9 cm, the radius is 15 cm)

Mathematics

2 answers:

Ugo [173]2 years ago

8 0

D is the answerr to the first one.

Illusion [34]2 years ago

6 0

1: Exact volume of cone = r^2 * h/ 3 = 15^2 * 9 / 3 = 225 * 9= 2025/3 = 675

2: Approximate volume of cone: pi* r^2 * h / 3 = 3.14 * 10^2 * 9/3 = 3.14 * 100* 9/3 = 3.14 x 900 / 3 = 2826/3 = 942 cm^3

3: Asks for the same as problem above, but we have to divide the diameter by 2 to get the radius first 10/2=5 now we can solve. : 3.14 * 5^2 * 5/3 = 3.14 * 25 * 5/ 3 = 3.14 * 125 / 3 = 392.5/ 3 = 130.8 m^3

The exact volume does not use pi: so that is why the first one is 675
The Approximate used pi or 3.14.

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What is the range for the possible side length AB of ABC?

julia-pushkina [17]

Answer:

2 < AB < 18

Step-by-step explanation:

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2 years ago

Solve for all values of x in simplest form. 9-4|3+5x|=5

Zinaida [17]

Answer:

$x=-2/5\text{ or } x=-4/5$

Step-by-step explanation:

So we have the equation:

$9-4|3+5x|=5$

First, subtract 9 from both sides:

$-4|3+5x|=-4$

Divide both sides by -4:

$|3+5x|=1$

Definition of Absolute Value:

$3+5x=1\text{ or } 3+5x=-1$

Subtract 3 from both sides:

$5x=-2\text{ or } 5x=-4$

Divide both sides by 5:

$x=-2/5\text{ or } x=-4/5$

And we're done!

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3 years ago

Read 2 more answers

1. What is the distance between the points (-3,0) and (3, 8) in the xy-plane?

olga_2 [115]

The answer is c
Ok please thanks me if I’m correct
If is not correct comment

8 0

3 years ago

A survey of 100 high school students provided this

HACTEHA [7]

Answer:

35/100

Step-by-step explanation:

You have to find how many juniors there are, so if you add 13, 20, and 2 you get 35. For the denominator you have to find the total number of students, so just add all of the numbers together to get 100. So there is a 35/100 chance that a randomly selected student is a junior.

5 0

1 year ago

The dimensions of a rectangle box are consecutive integers. If the box has volume of 13,800 cubic centimeters, what are its dime

klasskru [66]

Three consecutive integers are x, x+1, x+2.
The volume of a rectangular box is the product of its three dimensions. The volume is 138000 cm³.

$x(x+1)(x+2)=13800 \\
(x^2+x)(x+2)=13800 \\
x^3+2x^2+x^2+2x=13800 \\
x^3+3x^2+2x-13800=0 \\
x^3-23x^2+26x^2-598x+600x-13800=0 \\
x^2(x-23)+26x(x-23)+600(x-23)=0 \\
(x^2+26x+600)(x-23)=0 \\ 
x^2+26x+600=0 \ \lor \ x-23=0 \\ \\
1. \\
x^2+26x+600=0 \\ \\
a=1 \\ b=26 \\ c=600 \\ \Delta=b^2-4ac=26^2-4 \times 1 \times 600=676-2400=-1724 \\
\hbox{the discriminant is less than 0 so there are no real solutions} \\ \\
2. \\
x-23=0 \\
x=23 \\ \\
x+1=23+1 =24 \\ \\
x+2=23+2=25$

The dimensions of the box are 23 cm x 24 cm x 25 cm.

5 0

3 years ago