Question

Through a regular hexagon whose base edge is 8cm and whose height ii 12cma hole in the shape of the right prism with ots end being rhombus with diagonals of 6cm and 8cm is drilled find the total surface area and volume of the remaining soild?

Answer 1

The total surface area of the remaining solid is 48(4+✓3) centimeters square.

How to calculate the surface area?

Through a regular hexagonal prism whose base edge is 8 cm and the height is 12 cm, a hole in the shape of a right prism.

The formula for the total surface area will be:

= Total surface area=2(area of the base)+ parameter of base × height

where,

Height= 8cm

Parameter of base=12(2) = 24

Area of the base= 6×✓3/4×4² = 64✓3/4

The surface area of the remaining solid will be:

= 2(64✓3/4) + 24 × 8

= 2(64✓3/4 + 192

With the hole is a rhombus prism with the following parameters:

diagonal 1 = 6, diagonal 2 = 8, height = 12

The volume is:

V1 =0.5 × d1 × d2 × h

V1 = 0.5 × 6 × 8 × 12

V1 = 96

The dimensions of the hexagonal prism are:

Base edge (a) = 8

Height (h) = 12

The volume is

V2 = (3✓(3)/2)a²h

V2 = (3✓3)/2) × 8² × 12

V2 = 1152✓3

The remaining volume is

V = V2 -V1

V = 1152✓3 - 96

Learn more about the hexagonal prism on:

brainly.com/question/27127032

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