Through a regular hexagon whose base edge is 8cm and whose height ii 12cma hole in the shape of the right prism with ots end bei

Question

2 years ago

11

ng rhombus with diagonals of 6cm and 8cm is drilled find the total surface area and volume of the remaining soild?

1 answer:

guapka [62] · Answer 1 · 2023-03-03T21:55:10+03:00

The total surface area of the remaining solid is 48(4+✓3) centimeters square.

<h3>How to calculate the surface area?</h3>

Through a regular hexagonal prism whose base edge is 8 cm and the height is 12 cm, a hole in the shape of a right prism.

The formula for the total surface area will be:

= Total surface area=2(area of the base)+ parameter of base × height

where,

Height= 8cm

Parameter of base=12(2) = 24

Area of the base= 6×✓3/4×4² = 64✓3/4

The surface area of the remaining solid will be:

= 2(64✓3/4) + 24 × 8

= 2(64✓3/4 + 192

With the hole is a rhombus prism with the following parameters:

diagonal 1 = 6, diagonal 2 = 8, height = 12

The volume is:

V1 =0.5 × d1 × d2 × h

V1 = 0.5 × 6 × 8 × 12

V1 = 96

The dimensions of the hexagonal prism are:

Base edge (a) = 8

Height (h) = 12

The volume is

V2 = (3✓(3)/2)a²h

V2 = (3✓3)/2) × 8² × 12

V2 = 1152✓3

The remaining volume is

V = V2 -V1

V = 1152✓3 - 96

Learn more about the hexagonal prism on:

#SPJ4