The real solutions of f(x) = 0 is; x = -8, 0 and 4
<h3>How to find the roots of a polynomial graph?</h3>
When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.
Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.
From the given graph, the real solutions are at x = -8, 0 and 4
Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4
Read more about Polynomial roots graph at; brainly.com/question/14625910
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Y=10x+1
x=-1→y=10(-1)+1=-10+1→y=-9
x=0→y=10(0)+1=0+1→y=1
x=1→y=10(1)+1=10+1→y=11
x=5→y=10(5)+1=50+1→y=51
x y
-1 -9
0 1
1 11
5 51
Answer:
All three are yes
Step-by-step explanation:
4. yes
5.yes
6.yes
Answer:
F(8)=120
Step-by-step explanation:
f(x)=15x
f(8)=15(8)
f(8)=120
Answer:
17.8
Step-by-step explanation:
All you have to do is 8.9 x 2 = 17.8
HOPE HIS HELPS
