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3 years ago

Write an equation for the line that is parallel to the given line and that passes through the given point. y = –6x + 2; (–1, 2)

1 answer:

6 0

Parallel=same slope
Y=mx+b
Sub in the slope and point to solve for b
2=-6(-1)+b
2=6+b
2-6=b
-4=b
The equation is y=-6x-4; the answer is B
Hope this helps!

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Can someone plz answer this correctly and quickly.

rosijanka [135]

V = $\pi \pi$ $r^{2}$ h

1. Find the radius.

8/2 = 4

2. Square the radius.

$4^{2}$ = 16

3. Multiply that by pi.

3.14 * 16 = 50.24

4. Multiply that by the height.

50.24 * 20 = 1004.8

5. Now find 60% of that.

1004.8 * 0.6 = 602.88

V = 602.88 $m^{3}$

Honestly, it's been a while since I've done this, but I believe this is the answer.

7 0

3 years ago

Help me in major bed of some help

zzz [600]

It would be on both planes. When two planes intersect, they form a line along the points at which the two exist in the same place. Point V is said to exist along line s, which came from the intersection of the planes. This means that the point belongs to both of them.

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3 years ago

Help anyone can help me do 16 and 17 question,I will mark brainlest.The no 16 question is find the area of the shaded region

yanalaym [24]

Answer:

Question 16 = 22

Question 17 = 20 cm²

Step-by-step explanation:

Concepts:

Area of Square = s²

s = side

Area of Triangle = bh/2

b = base
h = height

Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Solve:

Question # 16

Step One: Find the total area of two squares

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

Step Two: Find the area of the blank triangle

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

Step Three: Subtract the area of the blank triangle from the total area

Total area = 29

Area of Square = 7

29 - 7 = 22

-----------------------------------------------------------

Question # 17

Step One: Find the length of PT

Given:

PR = 4 cm
RT = 6 cm

PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

PT = 10 cm

Step Two: Find the length of S to PT perpendicularly

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Three: Find the area of ΔPST

b = PT = 10 cm

h = S to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Four: Find the length of Q to PT perpendicularly

Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

Step Five: Find the area of ΔPQT

b = PT = 10 cm

h = Q to PT = 2 cm

A = bh / 2

A = (10)(2) / 2

A = 20 / 2

A = 10 cm²

Step Six: Combine area of two triangles to find the total area

Area of ΔPST = 10 cm²

Area of ΔPQT = 10 cm²

10 + 10 = 20 cm²

Hope this helps!! :)

Please let me know if you have any questions

6 0

3 years ago

What is the value of x when h(x) = −3?

CaHeK987 [17]

Answer:

○ -1

Step-by-step explanation:

Looking closely at this piecewise function, when the line on the left-hand side intersects at -3 = y, x is -1.

i hope this work for you

8 0

2 years ago

Choose the correct simplification of the expression (-11x^3y^12z^3)^0

Maurinko [17]

Answer:

Step-by-step explanation:

any thing raised to 0 will equal 1

6 0

4 years ago