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Ira Lisetskai [31]
3 years ago
8

Write a test program that prompts the user to enter a two dimensional array and displays the location of the smallest element in

the array.
Computers and Technology
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer:

def element_loc():

   is_end = 'n'

   dimen2 = []

   while is_end == 'n':

       par1 = input("Enter rows and columns: ").split(",")

       part = [int(i) for i in par1]

       dimen2. append(part)

       is_end = input("Do you want to add more rows? y/n: ")

   mini = list()

   for i in dimen2:

       mini. append(min(i))

   result = min(mini)

   row_index = mini. index(result)

   col_index = dimen2[row_index]. index(result)

   print("Row: ", row_index, "Col_index: ", col_index)

element_loc()

Explanation:

The python program solution above prompts users for the two-dimensional array and then the rows of the array are compared with the minimum value stored in another list or array. The row index and the column index are gotten from the mini and dimen2 arrays respectively and are displayed as the position of the minimum value in the two-dimensional array.

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Write a program to read as many test scores as the user wants from the keyboard (assuming at most 50 scores). Print the scores i
Oksana_A [137]

Answer: Provided in the explanation segment

Explanation:

Below is the code to carry out this program;

/* C++ program helps prompts user to enter the size of the array. To display the array elements, sorts the data from highest to lowest, print the lowest, highest and average value. */

//main.cpp

//include header files

#include<iostream>

#include<iomanip>

using namespace std;

//function prototypes

void displayArray(int arr[], int size);

void selectionSort(int arr[], int size);

int findMax(int arr[], int size);

int findMin(int arr[], int size);

double findAvg(int arr[], int size) ;

//main function

int main()

{

  const int max=50;

  int size;

  int data[max];

  cout<<"Enter # of scores :";

  //Read size

  cin>>size;

  /*Read user data values from user*/

  for(int index=0;index<size;index++)

  {

      cout<<"Score ["<<(index+1)<<"]: ";

      cin>>data[index];

  }

  cout<<"(1) original order"<<endl;

  displayArray(data,size);

  cout<<"(2) sorted from high to low"<<endl;

  selectionSort(data,size);

  displayArray(data,size);

  cout<<"(3) Highest score : ";

  cout<<findMax(data,size)<<endl;

  cout<<"(4) Lowest score : ";

  cout<<findMin(data,size)<<endl;

  cout<<"(5) Lowest scoreAverage score : ";

  cout<<findAvg(data,size)<<endl;

  //pause program on console output

  system("pause");

  return 0;

}

 

/*Function findAvg that takes array and size and returns the average of the array.*/

double findAvg(int arr[], int size)

{

  double total=0;

  for(int index=0;index<size;index++)

  {

      total=total+arr[index];

  }

  return total/size;

}

/*Function that sorts the array from high to low order*/

void selectionSort(int arr[], int size)

{

  int n = size;

  for (int i = 0; i < n-1; i++)

  {

      int minIndex = i;

      for (int j = i+1; j < n; j++)

          if (arr[j] > arr[minIndex])

              minIndex = j;

      int temp = arr[minIndex];

      arr[minIndex] = arr[i];

      arr[i] = temp;

  }

}

/*Function that display the array values */

void displayArray(int arr[], int size)

{

  for(int index=0;index<size;index++)

  {

      cout<<setw(4)<<arr[index];

  }

  cout<<endl;

}

/*Function that finds the maximum array elements */

int findMax(int arr[], int size)

{

  int max=arr[0];

  for(int index=1;index<size;index++)

      if(arr[index]>max)

          max=arr[index];

  return max;

}

/*Function that finds the minimum array elements */

int findMin(int arr[], int size)

{

  int min=arr[0];

  for(int index=1;index<size;index++)

      if(arr[index]<min)

          min=arr[index];

  return min;

}

cheers i hope this help!!!

8 0
3 years ago
Which activity does not allow a person to perform any work while at the shop
polet [3.4K]

Is it apprenticeship???:D

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3 years ago
Write an application that determines the value of the coins in a jar and prints the total in dollars and cents. Read integer val
pantera1 [17]

Answer: Result:Enter the number of quarters in the jar: 4

Enter the number of dimes in the jar: 5

Enter the number of nickels in the jar: 2

Enter the number of pennies in the jar: 5

Total value is 1 dollars and 65 cents

Explanation: import java.util.Scanner;public class Coins { public static void main(String[]args) { int quarters, dimes, nickels, pennies; int total;Scanner scan = new Scanner (System.in);System.out.print("Enter the number of quarters in the jar: "); quarters = scan.nextInt();System.out.print("Enter the number of dimes in the jar: ");dimes = scan.nextInt(); System.out.print("Enter the number of nickels in the jar: ");nickels= scan.nextInt(); System.out.print("Enter the number of pennies in the jar: ");pennies = scan.nextInt(); int total_cents = 25*quarters + dimes*10 + nickels*5 + pennies;total =total_cents/100;total_cents = total_cents %100;System.out.println("Total value is " + total + " dollars and " + total_cents + " cents ");}}

Result:Enter the number of quarters in the jar: 4

Enter the number of dimes in the jar: 5

Enter the number of nickels in the jar: 2

Enter the number of pennies in the jar: 5

Total value is 1 dollars and 65 cents

4 0
3 years ago
Read 2 more answers
Write an application that determines whether the first two files are located in the same folder as the third one. The program sh
marissa [1.9K]

Answer:

The program in Python is as follows:

fname1 = input("Filepath 1: ").lower()

fname2 = input("Filepath 2: ").lower()

fname3 = input("Filepath 3: ").lower()

f1dir = ""; f2dir = ""; f3dir = ""

fnamesplit = fname1.split("/")

for i in range(len(fnamesplit)-1):

   f1dir+=fnamesplit[i]+"/"

fnamesplit = fname2.split("/")

for i in range(len(fnamesplit)-1):

   f2dir+=fnamesplit[i]+"/"

fnamesplit = fname3.split("/")

for i in range(len(fnamesplit)-1):

   f3dir+=fnamesplit[i]+"/"

if f1dir == f2dir == f3dir:

   print("Files are in the same folder")

else:

   print("Files are in the different folder")

Explanation:

The next three lines get the file path of the three files

<em>fname1 = input("Filepath 1: ").lower()</em>

<em>fname2 = input("Filepath 2: ").lower()</em>

<em>fname3 = input("Filepath 3: ").lower()</em>

This initializes the directory of the three files to an empty string

f1dir = ""; f2dir = ""; f3dir = ""

This splits file name 1 by "/"

fnamesplit = fname1.split("/")

This iteration gets the directory of file 1 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f1dir+=fnamesplit[i]+"/"</em>

This splits file name 2 by "/"

fnamesplit = fname2.split("/")

This iteration gets the directory of file 2 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f2dir+=fnamesplit[i]+"/"</em>

This splits file name 3 by "/"

fnamesplit = fname3.split("/")

This iteration gets the directory of file 3 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f3dir+=fnamesplit[i]+"/"</em>

This checks if the file directories hold the same value

This is executed, if yes

<em>if f1dir == f2dir == f3dir:</em>

<em>    print("Files are in the same folder")</em>

This is executed, if otherwise

<em>else:</em>

<em>    print("Files are in the different folder")</em>

5 0
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zmey [24]

Answer:

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