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S_A_V [24]
3 years ago
7

Another brainliest help again

Mathematics
1 answer:
UkoKoshka [18]3 years ago
3 0

Answer:

Im pretty sure it is 2,4, and 5

Step-by-step explanation:

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Question:

The quantities x and y are proportional.

x\ \ \ \ \ \ \ \ \ \ y \\1\frac{2}{9}\ \ \ \ \ \ \ 2\frac{1}{3}

Find the constant of proportionality (r)

Answer:

r = 1\frac{10}{11}

Step-by-step explanation:

Given

x\ \ \ \ \ \ \ \ \ \ y \\1\frac{2}{9}\ \ \ \ \ \ \ 2\frac{1}{3}

Required

Determine the constant of proportionality (r)

Constant of proportionality (r) is calculated as

y = rx

When

y = 2\frac{1}{3}       x = 1\frac{2}{9}

Substitute these values in the given formula

2\frac{1}{3} = r * 1\frac{2}{9}

Convert both fractions to improper fractions

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Multiply both sides by \frac{9}{11}

\frac{7}{3} * \frac{9}{11}= r * \frac{11}{9} * \frac{9}{11}

\frac{7}{3} * \frac{9}{11}= r

Reorder

r = \frac{7}{3} * \frac{9}{11}

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Convert to mixed fraction

r = 1\frac{10}{11}

<em>Hence, the constant of proportionality is </em>1\frac{10}{11}<em></em>

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