Structure of <span>2,2-dimethyl-4-propyloctane is in the Word document below.
Answer is: six </span><span>secondary carbons.
</span>Secondary carbon (2°)<span> is attached to two other carbons. Secundary carbons are third, fifth, sixth and seventh in octane and first and second in propyl.
</span>Primary carbon (1°) is <span> attached to only </span>one <span>carbon.
</span>Tertiary carbon (3°)<span> is attached to three other carbons.
</span>Quaternary carbon (4°)<span> is attached to </span>four<span> other carbons.</span>
Answer:
1.33 × 10⁻³¹ m
Gamma rays
Explanation:
1 mol of photons required for the photoionization of N₂ has an energy (E) of 1495 kJ = 1495 × 10³ J = 1.495 × 10⁶ J. We can find the wavelength (λ) associated with this energy using the Planck-Einstein equation.
E = h . c . λ⁻¹
where,
h is the Planck's constant
c is the speed of light
E = h . c . λ⁻¹
λ = h . c . E⁻¹ = (6.63 × 10⁻³⁴ J.s) . (3.00 × 10⁸ m/s) . (1.495 × 10⁶ J)⁻¹ = 1.33 × 10⁻³¹ m
This wavelength corresponds to the Gamma rays region of the spectrum.
Start by adding ten to 90 then subtract ING one
Answer:
Making models
Explanation:
Classifying is the grouping together of items that are alike in some way. Answer: Making models involves creating rep- resentations of complex objects or processes.
