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Anvisha [2.4K]
3 years ago
10

There are three different dichloroethylenes (molecular formula C2H2Cl2), which we can designate X, Y, and Z. Compound X has no d

ipole moment, but compound Z does. Compounds X and Z each combine with hydrogen to give the same product: C2H2Cl2(X or Z) + H2 → ClCH2―CH2Cl What are the structures of X, Y, and Z? Be sure to include lone pair electrons. X draw structure ... Y draw structure ... Z draw structure ...

Chemistry
2 answers:
Amanda [17]3 years ago
7 0

Explanation:

The three options are:

1) Both Cl in the same carbon

2) One Cl in each C and both in the same side of the double bond (cis )

2) One Cl in each C and both in the oposite sides of the double bond (trans )

Options 2 and 3 are geometrical isomers and will generate the same products, so this options will be X and Z. Therefore Y is the one described in option 1.

Now, having the two electronegative atoms (Cl) in the same side will create a dipole moment but if they are oposed, the dipole moment will be canceled. Being that said we can affirm that the option 2) is Z and the option 3) is X

In the figure you can see the structures of X, Y and Z from top to bottom.

olya-2409 [2.1K]3 years ago
5 0

Answer:

Compound X= (E)-1,2-dichloroethene

Compound Y= 1,1-dichloroethene

Compound Z= (Z)-1,2-dichloroethene

Explanation:

In this case we will have <u>3 isomers</u> which have the same formula. If we use the formula, the options we have are that the chlorides are attached to the <u>same carbon</u> (compound Y) or <u>different carbons</u> (Compounds X and Y).

Now, the problem gives a clue about compounds X and Y,<u> hydrogenation results in the same compound</u> (see figure) therefore the only difference between the compounds is the <u>orientation of the Cl groups</u>, therefore one of them it must be <u>"E"</u> and the other <u>"Z"</u> (this <u>nomenclature should be used for alkenes</u>, since the cis / trans nomenclature is used for <u>other types of molecules</u>), so the question is which is the cis isomer and which is the Isomer Z ?

The problem says that <u>compound X has no dipole moment</u>, therefore in compound X the Cl groups must have <u>opposite directions</u> such that the dipole moments of both <u>cancel each other out</u>. In conclusion, compound X is the <u>isomer E</u>, compound Y is the compound in which the Cl groups are on the<u> same carbon</u> and compound z is the <u>isomer Z.</u>

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