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Anvisha [2.4K]
3 years ago
10

There are three different dichloroethylenes (molecular formula C2H2Cl2), which we can designate X, Y, and Z. Compound X has no d

ipole moment, but compound Z does. Compounds X and Z each combine with hydrogen to give the same product: C2H2Cl2(X or Z) + H2 → ClCH2―CH2Cl What are the structures of X, Y, and Z? Be sure to include lone pair electrons. X draw structure ... Y draw structure ... Z draw structure ...

Chemistry
2 answers:
Amanda [17]3 years ago
7 0

Explanation:

The three options are:

1) Both Cl in the same carbon

2) One Cl in each C and both in the same side of the double bond (cis )

2) One Cl in each C and both in the oposite sides of the double bond (trans )

Options 2 and 3 are geometrical isomers and will generate the same products, so this options will be X and Z. Therefore Y is the one described in option 1.

Now, having the two electronegative atoms (Cl) in the same side will create a dipole moment but if they are oposed, the dipole moment will be canceled. Being that said we can affirm that the option 2) is Z and the option 3) is X

In the figure you can see the structures of X, Y and Z from top to bottom.

olya-2409 [2.1K]3 years ago
5 0

Answer:

Compound X= (E)-1,2-dichloroethene

Compound Y= 1,1-dichloroethene

Compound Z= (Z)-1,2-dichloroethene

Explanation:

In this case we will have <u>3 isomers</u> which have the same formula. If we use the formula, the options we have are that the chlorides are attached to the <u>same carbon</u> (compound Y) or <u>different carbons</u> (Compounds X and Y).

Now, the problem gives a clue about compounds X and Y,<u> hydrogenation results in the same compound</u> (see figure) therefore the only difference between the compounds is the <u>orientation of the Cl groups</u>, therefore one of them it must be <u>"E"</u> and the other <u>"Z"</u> (this <u>nomenclature should be used for alkenes</u>, since the cis / trans nomenclature is used for <u>other types of molecules</u>), so the question is which is the cis isomer and which is the Isomer Z ?

The problem says that <u>compound X has no dipole moment</u>, therefore in compound X the Cl groups must have <u>opposite directions</u> such that the dipole moments of both <u>cancel each other out</u>. In conclusion, compound X is the <u>isomer E</u>, compound Y is the compound in which the Cl groups are on the<u> same carbon</u> and compound z is the <u>isomer Z.</u>

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Answer:

The molecular formula = N2O4

Explanation:

<u>Step 1</u>: Data given

A gaseous compound is 30.4 % N and 69.6%

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Volume of the gas = 1.00 L

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<u>Step 2</u>: Calculate mass of N

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<u>Step 4:</u> Calculate number of moles N

Number of moles N = Mass of N/ Molar mass of N

Moles of N = 1.596 grams / 14g/mol

Moles of N = 0.114 moles N

<u>Step 5:</u> Calculate moles of O

Moles O = 3.654 grams / 16 g/mol

Moles 0 = 0.2884 moles

<u>Step 6:</u> Calculate empirical formule

We calculate the empirical formule by dividing number of moles by the smallest number of mol

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O: 0.2284 / 0.114 = 2

Empirical formule = NO2

<u>Step 7: </u>Calculate number of moles of 5.25 g sample via gas law:

p*V = nRT

⇒ with p = the pressure = 1.26 atm

⇒ with v = 1.00 L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/ K*mol

⇒ with T = the temperature = 269 K

number of moles n = (p*V)/(R*T)

n = (1.26*1L)/(0.08206*269)

n = 0.057 mol  

<u>Step 8:</u> Calculate molar mass of the compound

This means 5.25 grams of the gas = 0.057 moles

So 1 mol of the compound has a molar mass of: 5.25 / 0.057 = 92.11 g/mol

<u>Step 9</u>: Calculate molar mass of the empirical formula NO2

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NO2 = 14 + 16 + 16 = 46 g/mol

The empirical formule NO2 has a molar mass of 46 g/mol

<u>Step 10</u>: Calculate molecular formula

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This means the empirical formula should be multiplied by 2

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