Step-by-step explanation:
Let √x - 1/√x = a
Squaring both the sides,
x + 1/x - 2 = a^2
Putting the value,
3–2√2 + 1/(3–2√2) - 2 = a^2
a^2 = 1 - 2√2 + 1/(3–2√2)
= [(3–2√2) (1–2√2) + 1] / 3–2√2
= {3 - 8√2 + 9} / 3–2√2
= [12 - 8√2] / 3–2√2
Rationalising both the sides
= {(12 - 8√2)(3+2√2)} ÷ (9–8)
= 36 + 24√2 - 24√2 + 16(2)
= 36 - 32
=> 4
a^2 = 4
a = √4
a = 2, -2
So,
√x - 1/√x = a = 2, -2.
Answer:
<h2><em>
D. (-7, 3)</em></h2>
Step-by-step explanation:
The standard form of a point slope equation of a line is expressed as shown;
y-y₀ = m(x-x₀) where;
m is the slope of the line
(x₀, y₀) is the coordinate of the point that lies in the line.
Comparing the standard equation given with the equation in question
y - 3 = 4(x + 7) to get the point on the line we will have;
y₀ = 3 and -x₀ = 7
for -x₀ = 7;
multiply both sides with a minus sign
-(-x₀) = -7
x₀ = -7
<em>Hence the coordinate of the point required (x₀, y₀) is (-7, 3).</em>
For one day he eats 3/4 cup of doog foods. For 7 days he eats 5 cup and 1/4 cup of food.
1/4×3=(1×3)/4=3/4
3/4×7=(3×7)/4=21/4
21/4=5 1/4.
Answer:
The area below the line is shaded.
Step-by-step explanation:
Using the zero-interval test [test point (0, 0)], we plug in 0 for both <em>y</em><em> </em>and <em>x</em><em> </em>to determine whether we shade <em>below the </em><em>line</em><em> </em>[the portion that DOES contain the origin] or <em>above</em><em> </em><em>the</em><em> </em><em>line</em><em> </em>[the portion that does not contain the origin]. This is where me must verify the inequality as false or true:
![\displaystyle 0 < 2[0] + 1 → 0 < 1](https://tex.z-dn.net/?f=%5Cdisplaystyle%200%20%3C%202%5B0%5D%20%2B%201%20%E2%86%92%200%20%3C%201)
This is a genuine statement, therefore we shade <em>below</em><em> </em><em>the</em><em> </em><em>line</em>.
I am joyous to assist you anytime.
