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alexandr402 [8]
3 years ago
13

G6 M4 L19

Mathematics
1 answer:
BigorU [14]3 years ago
5 0

Answer:

24. because 2009-2005+20 = 24. hope that helps

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The initial population of a town is 1,300 and it is increasing at the rate of 3% each year. Find the population at 12 years​
stepan [7]

Answer:

1300 * (1 + 0.03)^12 = 1853

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Write the equation in slope intercept form. what are the slope and y-intercept?
Leno4ka [110]
Slope intercept is basically solve for y
y=mx+b
m=slope
b=yintercept

-3x-10y=7
add 3x to both sides
-10y=3x+7
divide both sides by -10
y=-3/10x-7/10

slope is -3/10
yintercept is -7/10 or at point (0,-7/10)
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What is 100.34567 in a fraction and word form? Thank you! ❤
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3 years ago
What is the ratio from 18 to 16
Irina18 [472]

Answer: 8:9

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4 0
4 years ago
4. Two savings accounts each start with a $200 principal and have an interest rate of 5%. One account earns simple interest and
slega [8]

Answer:

The compounded annually account will earn more interest over 10 years

Step-by-step explanation:

The rule of the simple interest is I = Prt, where

  • P is the original value
  • r is the rate in decimal
  • t is the time

The rule of the compounded interest is A = P(1+\frac{r}{n})^{nt}, where

  • A is the new value
  • P is the original value
  • r is the rate in decimal
  • n is the number of periods
  • t is the time

The interest I = A - P

∵ Each account start with $200

∴ P = 200

∵ They have an interest rate of 5%

∴ r = 5% = 5 ÷ 100 = 0.05

∵ One account earns simple interest and the other is compounded  

   annually

∴ n = 1 ⇒ compounded annually

∵ The time is 10 years

∴ t = 10

→ Substitute these values in the two rules above

∵ I = 200(0.05)(10)

∴ I = 100

∴ The simple interest = $100

∵ I = A - P

∵ A = 200(1+\frac{0.05}{1})^{1(10)}

∴ A = 325.7789254

∵ I = 325.7789254 - 200

∴ I = 125.7789254

∴ The compounded interest = $125.7789254

∵ The simple interest is $100

∵ The compounded interest is $125.7789254

∵ $125.7789254 > $100

∴ The compounded annually account will earn more interest

   over 10 years

6 0
3 years ago
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