So then what is the question?
so you use the formula a^2 + b^2 = c^2
so C will be JL
13m^2 + 17m^2 = c^2
458 m = c^2
to leave C alone you need to square root it
√458m = √c^2
21.4 = C
Answer:
aa
Step-by-step explanation:
Answer:
64.5°
Step-by-step explanation:
it is the answer got it nd comment me
The adjoint of the matrix
is ![\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%260%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
<h3>How to determine the adjoint?</h3>
The matrix is given as:
![\left[\begin{array}{cc}1&0\\2&-1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C2%26-1%5Cend%7Barray%7D%5Cright%5D)
For a matrix A be represented as:
![A = \left[\begin{array}{cc}a&b\\c&d\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D)
The adjoint is:
![Adj = \left[\begin{array}{cc}d&-b\\-c&a\end{array}\right]](https://tex.z-dn.net/?f=Adj%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dd%26-b%5C%5C-c%26a%5Cend%7Barray%7D%5Cright%5D)
Using the above format, we have:
![Adj = \left[\begin{array}{cc}-1&0\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=Adj%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%260%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
Hence, the adjoint of the matrix
is ![\left[\begin{array}{cc}-1&0\\-2&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%260%5C%5C-2%261%5Cend%7Barray%7D%5Cright%5D)
Read more about matrix at:
brainly.com/question/11989522
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